NEET 2016 Phase 2 · PhysicsPower factorPrevious Year Question
The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an L-C-R circuit. The power factor of this circuit is
Answer: (C) 0.8. Answer: (C) 0.8 Solution: cos φ = V_R / V = 80 / √(V_R² + (V_L − V_C)²) = 80 / √(80² + (100 − 40)²) = 80/√(6400 + 3600) = 80/100 = 0.8.
- A.0.4
- B.0.5
- C.0.8✓
- D.1.0
Correct Answer
(C) 0.8
Solution & Explanation
Answer: (C) 0.8 Solution: cos φ = V_R / V = 80 / √(V_R² + (V_L − V_C)²) = 80 / √(80² + (100 − 40)²) = 80/√(6400 + 3600) = 80/100 = 0.8.
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