NEET 2016 Phase 2 · PhysicsImpedancePrevious Year Question
A 100 Ω resistance and a capacitor of 100 Ω reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is
Answer: (A) 2.2 A. Answer: (A) 2.2 A Solution: R = 100 Ω, X_C = 100 Ω, so Z = √(100² + 100²) = 100√2 Ω.
- A.2.2 A✓
- B.11 A
- C.4.4 A
- D.11√2 A
Correct Answer
(A) 2.2 A
Solution & Explanation
Answer: (A) 2.2 A Solution: R = 100 Ω, X_C = 100 Ω, so Z = √(100² + 100²) = 100√2 Ω. Peak voltage = 220√2 V. I_peak = 220√2/(100√2) = 2.2 A (the displacement current equals the conduction current in a series circuit).
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