NEET 2016 Phase 2 · PhysicsQuality factorPrevious Year Question
Which of the following combinations should be selected for better tuning of an L-C-R circuit used for communication?
Answer: (C) R = 15 Ω, L = 3.5 H, C = 30 μF. Answer: (C) R = 15 Ω, L = 3.5 H, C = 30 μF Solution: Better tuning means low bandwidth = R/L (sharper resonance, higher Q-factor).
- A.R = 20 Ω, L = 1.5 H, C = 35 μF
- B.R = 25 Ω, L = 2.5 H, C = 45 μF
- C.R = 15 Ω, L = 3.5 H, C = 30 μF✓
- D.R = 25 Ω, L = 1.5 H, C = 45 μF
Correct Answer
(C) R = 15 Ω, L = 3.5 H, C = 30 μF
Solution & Explanation
Answer: (C) R = 15 Ω, L = 3.5 H, C = 30 μF Solution: Better tuning means low bandwidth = R/L (sharper resonance, higher Q-factor). Option C has the lowest R and the highest L, giving the smallest R/L bandwidth.
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