Which of the following reactions is appropriate for converting acetamide to methanamine ?
Answer: (B) (B) Hoffmann hypobromamide (bromamide) reaction. \textbf{Answer:} (B) Hoffmann bromamide degradation converts an amide to a primary amine with ONE fewer carbon atom.
- A.(A) Carbylamine reaction
- B.(B) Hoffmann hypobromamide (bromamide) reaction✓
- C.(C) Stephen's reaction
- D.(D) Gabriel's phthalimide synthesis
Correct Answer
(B) (B) Hoffmann hypobromamide (bromamide) reaction
Solution & Explanation
\textbf{Answer:} (B) Hoffmann bromamide degradation converts an amide to a primary amine with ONE fewer carbon atom. \textbf{Solution:} Acetamide has two carbons; methanamine has one carbon. The Hoffmann bromamide (hypobromite) degradation, , converts a primary amide to a primary amine with the loss of one carbon (as carbonate via an isocyanate intermediate, effectively loss of ). This carbon-count change exactly matches . The carbylamine reaction (A) is a TEST for primary amines, not a preparation. Stephen's reaction (C) reduces nitriles to aldehydes. Gabriel synthesis (D) makes amines from alkyl halides, not from amides. Hence (B).
