A mixture of 2.3 g formic acid (HCOOH) and 4.5 g oxalic acid ((COOH)2) is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. The weight (in g) of the remaining gas at STP will be

Correct answer: (A) (A) 2.8. Answer: (A) 2.8 g. Solution: Conc. H2SO4 dehydrates the acids: HCOOH ->[conc. H2SO4] CO + H2O and (COOH)2 ->[conc. H2SO4] CO + CO2 + H2O. Moles: HCOOH = 2.3/46 = 1/20 mol giving 1/20 mol CO; (COOH)2 = 4.5/90 = 1/20 mol giving 1/20 mol CO and 1/20 mol CO2. KOH absorbs the acidic CO2, leaving CO: total = 2/20 mol, so mass = (2/20)× 28 = 2.8 g.

NEET 2018 · ChemistryDerivative reactivityPrevious Year Question

A mixture of 2.3 g formic acid ( $HCOOH$ ) and 4.5 g oxalic acid ( $(COOH) X_{2}$ ) is treated with conc. $H X_{2} SO X_{4}$ . The evolved gaseous mixture is passed through $KOH$ pellets. The weight (in g) of the remaining gas at STP will be

Answer: (A) (A) 2.8. \textbf{Answer:} (A) 2.8 g.

A.(A) 2.8✓
B.(B) 3.0
C.(C) 1.4
D.(D) 4.4

Correct Answer

(A) (A) 2.8

Solution & Explanation

\textbf{Answer:} (A) 2.8 g. \textbf{Solution:} Conc. $H X_{2} SO X_{4}$ dehydrates the acids: $HCOOH conc \cdot H X_{2} SO X_{4} CO + H X_{2} O$ and $(COOH) X_{2} conc \cdot H X_{2} SO X_{4} CO + CO X_{2} + H X_{2} O$ . Moles: $HCOOH = 2.3/46 = 1/20$ mol giving $1/20$ mol $CO$ ; $(COOH) X_{2} = 4.5/90 = 1/20$ mol giving $1/20$ mol $CO$ and $1/20$ mol $CO X_{2}$ . $KOH$ absorbs the acidic $CO X_{2}$ , leaving $CO$ : total $= 2/20$ mol, so mass $= (2/20) \times 28 = 2.8$ g.

🎯

43,000+ questions in हिंदी & English · one-tap toggle

Practice NEET 2018 Chemistry — free, with instant solutions

The app builds a daily goal from your weak topics and brings each question back just before you forget it — so what you solve today turns into marks on exam day.

Open →📚Practice all NEET Chemistry PYQs chapter-wise →💡Don't get it? Learn the Aldehydes, Ketones And Carboxylic Acid concepts →

← Chemistry Q14 Chemistry Q16 →

More NEET PYQ solutions

ChemReagents which can be used to convert alcohols to carboxylic acids are: (A) CrO3 - H2SO4 (B) K2Cr2O7 + H2SO4 (C) KMnO4 + KOH/H3O+ (D) Cu, 573 K (E) CrO3, (CH3CO)2O Choose the most appropriate answer:ChemIdentify the product in the following reaction: cyclobutyl chloride ->[(i) KCN][(ii) H2O/HCl, ] ->[(iii) Br2/red P][(iv) H2O] Product.ChemMatch List-I with List-II and choose the correct answer. List-I: (a) C6H6 ->[CO, HCl][Anhy. AlCl3, CuCl] C6H5-CHO (b) R-CO-CH3 ->[NaOX] R-COO^- + CHX3 (c) R-CH2-OH + R'COOH ->[Conc. H2SO4] (d) R-CH2-COOH ->[(i) X2/Red P][(ii) H2O] List-II: (i) Hell-Volhard-Zelinsky reaction (ii) Gattermann-Koch reaction (iii) Haloform reaction (iv) Esterification ChemConsider the reaction: CH3CH2COONa ->[NaOH + ?][ ] CH3CH3 + Na2CO3 Identify the missing reagent.ChemThe major product of the following reaction is: benzene-1,2-dicarboxylic acid (phthalic acid) ->[NH3][strong heating] ?ChemThe correct order of decreasing acidity of the following aliphatic acids is:ChemWhich one of the following reactions does NOT belong to Lassaigne's test?ChemHow many products (including stereoisomers) are expected from the monochlorination of 2-methylbutane, (CH3)2CH-CH2-CH3?

More: All NEET 2018 Chemistry PYQs · NEET Chemistry PYQs · All NEET PYQs · Previous year papers

A mixture of 2.3 g formic acid (HCOOH) and 4.5 g oxalic acid ((COOH)X2​) is treated with conc. HX2​SOX4​. The evolved gaseous mixture is passed through KOH pellets. The weight (in g) of the remaining gas at STP will be

Solution & Explanation

More NEET PYQ solutions

A mixture of 2.3 g formic acid ( $HCOOH$ ) and 4.5 g oxalic acid ( $(COOH) X_{2}$ ) is treated with conc. $H X_{2} SO X_{4}$ . The evolved gaseous mixture is passed through $KOH$ pellets. The weight (in g) of the remaining gas at STP will be