The major product of the following reaction is: benzene-1,2-dicarboxylic acid (phthalic acid) ?
Answer: (B) (B) Phthalimide (benzene fused to a five-membered cyclic imide). \textbf{Answer:} (B) Phthalimide (benzene fused to a five-membered cyclic imide) \textbf{Solution:} Phthalic acid reacts with ammonia to give the ammonium salt/diamide, which on strong heating undergoes intramolecular cyclodehydration (loss of water and ammonia).
- A.(A) Aromatic ring bearing one and one group (mono-amide)
- B.(B) Phthalimide (benzene fused to a five-membered cyclic imide)✓
- C.(C) Aromatic ring bearing one and one group (anthranilic-acid type)
- D.(D) Aromatic ring bearing two groups (ortho-diamine)
Correct Answer
(B) (B) Phthalimide (benzene fused to a five-membered cyclic imide)
Solution & Explanation
\textbf{Answer:} (B) Phthalimide (benzene fused to a five-membered cyclic imide) \textbf{Solution:} Phthalic acid reacts with ammonia to give the ammonium salt/diamide, which on strong heating undergoes intramolecular cyclodehydration (loss of water and ammonia). The two ortho carboxyl groups close onto a single nitrogen to form a five-membered cyclic imide fused to the benzene ring, namely phthalimide.
