NEET 2019 Odisha · ChemistryRosenmundPrevious Year Question
When the vapours of a secondary alcohol are passed over heated copper at 573 K, the product formed is:
Answer: (C) (C) a ketone. \textbf{Answer:} (C) a ketone \textbf{Solution:} Catalytic dehydrogenation over heated copper at 573 K removes from the carbinol carbon.
- A.(A) a carboxylic acid
- B.(B) an aldehyde
- C.(C) a ketone✓
- D.(D) an alkene
Correct Answer
(C) (C) a ketone
Solution & Explanation
\textbf{Answer:} (C) a ketone \textbf{Solution:} Catalytic dehydrogenation over heated copper at 573 K removes from the carbinol carbon. In a secondary alcohol such as the carbinol carbon carries two alkyl groups and one H, so loss of gives a ketone, e.g. . (Primary alcohols give aldehydes; tertiary alcohols dehydrate to alkenes.)
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