NEET 2023 Phase 1 · PhysicsDipole torquePrevious Year Question
An electric dipole is placed at an angle of 30° with an electric field of intensity 2 × 10⁵ N C⁻¹. It experiences a torque equal to 4 N m. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.
Answer: (D) 2 mC. Answer: (d) Solution: Torque on a dipole in a uniform field: τ = pE sinθ, where p = qL.
- A.8 mC
- B.6 mC
- C.4 mC
- D.2 mC✓
Correct Answer
(D) 2 mC
Solution & Explanation
Answer: (d) Solution: Torque on a dipole in a uniform field: τ = pE sinθ, where p = qL. So τ = qLE sinθ. Given: τ = 4 N m, E = 2 × 10⁵ N C⁻¹, L = 2 cm = 0.02 m, θ = 30° → sin30° = 0.5. Solve for q: q = τ / (L E sinθ) = 4 / [(0.02)(2 × 10⁵)(0.5)] q = 4 / (2000) = 2 × 10⁻³ C = 2 mC. Hence the charge magnitude is 2 mC.
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