NEET 2023 Phase 2 · PhysicsElectron λPrevious Year Question
The de Broglie wavelength associated with an electron, accelerated by a potential difference of 81 V, is given by:
Answer: (B) 0.136 nm. Answer: (b) 0.136 nm Solution: λ = 12.27/√V Å = 12.27/√81 = 12.27/9 ≈ 1.36 Å.
- A.1.36 nm
- B.0.136 nm✓
- C.13.6 nm
- D.136 nm
Correct Answer
(B) 0.136 nm
Solution & Explanation
Answer: (b) 0.136 nm Solution: λ = 12.27/√V Å = 12.27/√81 = 12.27/9 ≈ 1.36 Å. = 1.36 × 10⁻¹⁰ m = 0.136 nm.
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