NEET 2023 Phase 2 · PhysicsSurface gPrevious Year Question

If R is the radius of the earth and g the acceleration due to gravity on its surface, the mean density of the earth is:

Answer: (A) 3g/(4πRG). Correct Answer (A): 3g/(4πRG) Solution: g = GM/R² with M = ρ(4/3)πR³ ⇒ g = (4/3)πGRρ ⇒ ρ = 3g/(4πGR).

  1. A.3g/(4πRG)
  2. B.4πgR/(3G)
  3. C.12πg/(RG)
  4. D.4πgG/(3R)

Correct Answer

(A) 3g/(4πRG)

Solution & Explanation

Correct Answer (A): 3g/(4πRG) Solution: g = GM/R² with M = ρ(4/3)πR³ ⇒ g = (4/3)πGRρ ⇒ ρ = 3g/(4πGR).

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