NEET 2024 · ChemistryArrheniusPrevious Year Question

Activation energy of any chemical reaction can be calculated if one knows the value of

Answer: (C) rate constants at two different temperatures.. \textbf{Answer:} (C) rate constants at two different temperatures \textbf{Solution:} From the Arrhenius equation $k = A e^{- E_{a} / R T}$ , comparing the rate constant at two different temperatures $T_{1}$ and $T_{2}$ gives the two-temperature form: $lo g \frac{k _{2}}{k _{1}} = \frac{E _{a}}{2.303 R} (\frac{T _{2} - T _{1}}{T _{1} T _{2}})$ Knowing the rate constants $k_{1}$ and $k_{2}$ at two different temperatures $T_{1}$ and $T_{2}$ allows the activation energy $E_{a}$ to be calculated.

A.Probability of collision.
B.Orientation of reactant molecules.
C.rate constants at two different temperatures.✓
D.rate constant at standard temperature.

Correct Answer

Solution & Explanation

\textbf{Answer:} (C) rate constants at two different temperatures \textbf{Solution:} From the Arrhenius equation $k = A e^{- E_{a} / R T}$ , comparing the rate constant at two different temperatures $T_{1}$ and $T_{2}$ gives the two-temperature form: $lo g \frac{k _{2}}{k _{1}} = \frac{E _{a}}{2.303 R} (\frac{T _{2} - T _{1}}{T _{1} T _{2}})$ Knowing the rate constants $k_{1}$ and $k_{2}$ at two different temperatures $T_{1}$ and $T_{2}$ allows the activation energy $E_{a}$ to be calculated.

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