NEET 2024 · PhysicsIdeal gasPrevious Year Question
The volume occupied by 1.8 g of water vapour at 374 °C and 1 bar pressure will be: [Use R = 0.083 bar L K⁻¹ mol⁻¹]
Answer: (D) 5.37 L. Correct Answer (D): 5.37 L This is a direct application of the ideal gas equation PV = nRT.
- A.96.66 L
- B.55.87 L
- C.3.10 L
- D.5.37 L✓
Correct Answer
(D) 5.37 L
Solution & Explanation
Correct Answer (D): 5.37 L This is a direct application of the ideal gas equation PV = nRT. The amount of water vapour is n = mass/molar mass = 1.8 g / 18 g mol⁻¹ = 0.1 mol. The temperature must be in kelvin: 374 °C = 647 K. With P = 1 bar and R = 0.083 bar L K⁻¹ mol⁻¹, V = nRT/P ≈ 5.37 L.
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