NEET 2024 · PhysicsCapacitive reactancePrevious Year Question
A 10 μF capacitor is connected to a 210 V, 50 Hz source as shown in figure. The peak current in the circuit is nearly (π = 3.14):
Answer: (A) 0.93 A. Answer: (A) 0.93 A Solution: Capacitive reactance X_C = 1/(ωC) = 1/(2π × 50 × 10×10⁻⁶) = 1000/π Ω.

- A.0.93 A✓
- B.1.20 A
- C.0.35 A
- D.0.58 A
Correct Answer
(A) 0.93 A
Solution & Explanation
Answer: (A) 0.93 A Solution: Capacitive reactance X_C = 1/(ωC) = 1/(2π × 50 × 10×10⁻⁶) = 1000/π Ω. Peak current i₀ = (√2 · V_rms)/X_C = (√2 × 210)/(1000/π) ≈ 0.93 A.
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