NEET 2026 (Phase 1) · ChemistryRate lawPrevious Year Question
Match List I with List II : List-I (Order of reaction) (A) Zero order (B) First order (C) Second order (D) Third order List-II (Unit of rate constant) (I) $\text{mol}^{-1}\,\text{L}\,\text{s}^{-1}$ (II) $\text{mol}^{-2}\,\text{L}^2\,\text{s}^{-1}$ (III) $\text{s}^{-1}$ (IV) $\text{mol}\,\text{L}^{-1}\,\text{s}^{-1}$ Choose the correct answer from the options given below :
- A.(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
- B.(A)-(IV), (B)-(III), (C)-(I), (D)-(II)✓
- C.(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- D.(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
Correct Answer
(B) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Solution & Explanation
\textbf{Answer:} (B) (A)-(IV), (B)-(III), (C)-(I), (D)-(II) \textbf{Solution:} The unit of the rate constant for an $n$th order reaction is $(\text{mol}\,\text{L}^{-1})^{1-n}\,\text{s}^{-1} = \text{mol}^{1-n}\,\text{L}^{n-1}\,\text{s}^{-1}$ Zero order $(n=0)$: $\text{mol}\,\text{L}^{-1}\,\text{s}^{-1} \to$ (IV) First order $(n=1)$: $\text{s}^{-1} \to$ (III) Second order $(n=2)$: $\text{mol}^{-1}\,\text{L}\,\text{s}^{-1} \to$ (I) Third order $(n=3)$: $\text{mol}^{-2}\,\text{L}^2\,\text{s}^{-1} \to$ (II) Hence (A)-(IV), (B)-(III), (C)-(I), (D)-(II).
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