NEET 2026 (Phase 1) · ChemistryPrevious Year Question

The number of chlorine atoms present in the organic products $X$ and $Y$ of the following reactions, respectively, are : $C X_{6} H X_{6} + 6 Cl X_{2} anhyd. AlCl3 dark, cold$ $X$ $C X_{6} H X_{6} + 3 Cl X_{2} UV 500 K$ $Y$

Answer: (C) (C) 6 and 6. With anhydrous $AlCl X_{3}$ , benzene undergoes electrophilic aromatic substitution; exhaustive chlorination replaces all six ring hydrogens to give hexachlorobenzene $C X_{6} Cl X_{6}$ ( $X$ ), which contains 6 chlorine atoms.

A.(A) 3 and 3
B.(B) 6 and 3
C.(C) 6 and 6✓
D.(D) 3 and 6

Correct Answer

Solution & Explanation

With anhydrous $AlCl X_{3}$ , benzene undergoes electrophilic aromatic substitution; exhaustive chlorination replaces all six ring hydrogens to give hexachlorobenzene $C X_{6} Cl X_{6}$ ( $X$ ), which contains 6 chlorine atoms. Under UV light, $Cl X_{2}$ adds across the ring by a free-radical addition: $C X_{6} H X_{6} + 3 Cl X_{2} C X_{6} H X_{6} Cl X_{6}$ (benzene hexachloride / BHC, $Y$ ), also containing 6 chlorine atoms. Hence 6 and 6.

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The number of chlorine atoms present in the organic products X and Y of the following reactions, respectively, are : CX6​HX6​+6ClX2​anhyd. AlCl3dark, cold​ X CX6​HX6​+3ClX2​UV500 K​ Y

Solution & Explanation

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The number of chlorine atoms present in the organic products $X$ and $Y$ of the following reactions, respectively, are : $C X_{6} H X_{6} + 6 Cl X_{2} anhyd. AlCl3 dark, cold$ $X$ $C X_{6} H X_{6} + 3 Cl X_{2} UV 500 K$ $Y$