The major product Z formed in the following sequence of reactions is C2H6 ->[Cl2][UV] X ->[NH3] Y ->[(i) NaNO2/HCl][(ii) H2O] Z

Correct answer: (C) (C) C2H5OH. Free-radical chlorination of ethane gives chloroethane C2H5Cl (X). Ammonolysis (nucleophilic substitution by NH3) gives ethylamine C2H5NH2 (Y). A primary aliphatic amine on diazotisation with NaNO2/HCl forms an unstable diazonium salt that is hydrolysed by water to the alcohol: C2H5NH2 ->[NaNO2/HCl][H2O] C2H5OH (Z, ethanol).

NEET 2026 (Phase 1) · ChemistryPrevious Year Question

The major product $Z$ formed in the following sequence of reactions is $C X_{2} H X_{6} Cl X_{2} UV$ $X$ $NH X_{3}$ $Y$ $(i) NaNO2/HCl (ii) H2O$ $Z$

Answer: (C) (C) $C X_{2} H X_{5} OH$ . Free-radical chlorination of ethane gives chloroethane $C X_{2} H X_{5} Cl$ ( $X$ ).

A.(A) $C X_{2} H X_{5} NO X_{2}$
B.(B) $CH X_{3} - N = N - OH$
C.(C) $C X_{2} H X_{5} OH$ ✓
D.(D) $C X_{2} H X_{5} NH X_{2}$

Correct Answer

Solution & Explanation

Free-radical chlorination of ethane gives chloroethane $C X_{2} H X_{5} Cl$ ( $X$ ). Ammonolysis (nucleophilic substitution by $NH X_{3}$ ) gives ethylamine $C X_{2} H X_{5} NH X_{2}$ ( $Y$ ). A primary aliphatic amine on diazotisation with $NaNO X_{2} / HCl$ forms an unstable diazonium salt that is hydrolysed by water to the alcohol: $C X_{2} H X_{5} NH X_{2} NaNO X_{2} / HCl H X_{2} O C X_{2} H X_{5} OH$ ( $Z$ , ethanol).

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The major product Z formed in the following sequence of reactions is CX2​HX6​ClX2​UV​ X NHX3​​ Y (i) NaNO2/HCl(ii) H2O​ Z

Solution & Explanation

More NEET PYQ solutions

The major product $Z$ formed in the following sequence of reactions is $C X_{2} H X_{6} Cl X_{2} UV$ $X$ $NH X_{3}$ $Y$ $(i) NaNO2/HCl (ii) H2O$ $Z$