Resistance When a Wire Is Cut, Folded or Rejoined

Physics · Current Electricity · NEET

When you cut a wire of resistance R into n equal parts, each part has resistance R/n (length drops, so resistance drops). If you then join all n parts in parallel (or fold the wire n times), the total becomes R/n². Memory hook: cutting divides by n, folding divides by n squared.
Cutting vs Folding a wire of resistance RFull wire = R (length L)Cut into n=4 parts → each part = R/44 parts inparallel (fold)= R/16 = R/n²Cut → divide by nR/n eachCut + all parallel (fold)→ divide by n² → R/n²
Cutting a wire into n equal parts gives each part R/n. Joining all n parts in parallel (same as folding the wire) gives R/n squared, shown here for n = 4 giving R/16.

Your doubts, answered

If a wire of resistance R is cut into n equal parts, what is the resistance of each part?

Each part has resistance R/n. Resistance is R = rho L / A. Cutting into n equal parts keeps the area A and resistivity rho the same, but each piece now has length L/n. So each piece has resistance rho (L/n) / A = R/n. Example: a 12 ohm wire cut into 3 equal parts gives three 4 ohm pieces.

Why does folding a wire (or joining all parts in parallel) give R/n squared?

Two steps happen. First, folding a wire into n equal layers is the same as cutting it into n parts each of resistance R/n. Second, these n equal parts now sit side by side (in parallel), so the equivalent resistance is (R/n) divided by n = R/n squared. Cutting divides by n, then parallel joining divides by n again, so overall it is R/n squared.

Does cutting or folding a wire change its resistivity?

No. Resistivity (rho) is a material property. It depends only on the material and temperature, not on the shape, length or how you cut the wire. Cutting changes the resistance R because length and area change, but rho stays the same. This is a very common NEET trap.

A wire is cut into two halves and the halves are connected in parallel. What is the new resistance?

Start with resistance R. Cut into 2 equal halves, each half is R/2. Connect the two R/2 halves in parallel: 1/Req = 1/(R/2) + 1/(R/2) = 4/R, so Req = R/4. This matches the R/n squared rule with n = 2, giving R/4.

How is cutting a wire different from stretching a wire?

Cutting keeps the area the same and only shortens the length, so each of n parts is R/n. Stretching keeps the volume constant: if length becomes n times, area becomes 1/n times, and resistance becomes n squared R. So cutting reduces resistance while stretching increases it. Do not mix the two formulas.

⚠️ The NEET trap
Cutting a wire into n parts makes each part have resistance nR because the wire is now 'divided'.
Each part has resistance R/n. A shorter length means less resistance (R is proportional to length). The full wire R splits into n equal shorter pieces, so each is R/n.
🧠 Cut = shorter = smaller resistance. Each piece is R/n, never nR. Only stretching makes resistance larger.

Real NEET questions

NEET 2024

A wire of resistance 100 ohm is divided into 10 equal parts. The first 5 are connected in series and the next 5 in parallel; the two combinations are then joined in series. The resistance of the final combination is:

A · 52 ohm
B · 55 ohm
C · 60 ohm
D · 26 ohm
Solution: Step 1: Each of the 10 equal parts has resistance 100/10 = 10 ohm. Step 2: Five parts in series = 10 + 10 + 10 + 10 + 10 = 50 ohm. Step 3: Five parts in parallel = 10/5 = 2 ohm. Step 4: The two combinations in series = 50 + 2 = 52 ohm. Answer: 52 ohm (A).
NEET 2025

A wire of resistance R is cut into 8 equal pieces. Two sets are made by joining four pieces in parallel each; the two sets are then connected in series. The net resistance is:

A · R/16
B · R/8
C · R/64
D · R/32
Solution: Step 1: Each of the 8 equal pieces has resistance R/8. Step 2: Four pieces in parallel = (R/8)/4 = R/32 (one set). Step 3: Two such sets in series = R/32 + R/32 = R/16. Answer: R/16 (A).

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Frequently asked

What is the resistance of each piece if a wire of resistance R is cut into n equal parts?

Each piece has resistance R/n, because the length of each piece is L/n while area and resistivity stay the same.

What is the resistance when all n cut pieces are joined in parallel?

It becomes R/n squared. Each piece is R/n, and n equal R/n resistors in parallel give (R/n)/n = R/n squared.

Is folding a wire in half the same as connecting the two halves in parallel?

Yes. Folding a wire into two equal layers makes the two halves (each R/2) carry current side by side, which is a parallel connection giving R/4.

Why doesn't cutting change resistivity?

Resistivity depends only on the material and temperature. Cutting only changes physical dimensions (length and area), which change resistance R, not resistivity rho.

How do I quickly solve NEET cut-wire problems?

First find each piece as R/n. Then apply series (add) or parallel (reciprocal add) to the given arrangement. All-parallel of n pieces gives R/n squared directly.