de Broglie Wavelength of a Thermal Neutron

Physics · Dual Nature Of Radiation And Matter · NEET

A thermal neutron is a neutron that is in thermal equilibrium with its surroundings, so its average kinetic energy is (3/2)kT. Its de Broglie wavelength is lambda = h / sqrt(3 m k T). Memory hook: "thermal means 3kT/2 energy, and the 3 lives under the square root."
de Broglie Wavelength of a Thermal NeutronThermal equilibriumKE = (3/2) k TMomentump = sqrt(3 m k T)Wavelengthlambda = h/plambda = h / sqrt(3 m k T)3 directions of motion put a 3 under the root (not a 2). T is in kelvin.
A thermal neutron's average kinetic energy (3/2)kT gives momentum sqrt(3mkT), so its de Broglie wavelength is lambda = h/sqrt(3mkT). The 3 comes from motion in three directions.

Your doubts, answered

Why is the kinetic energy of a thermal neutron (3/2)kT and not kT?

A free neutron in a gas moves in all three directions: x, y and z. The kinetic theory says each direction of motion carries an average energy of (1/2)kT. This is called equipartition of energy. Three directions give 3 times (1/2)kT = (3/2)kT. So the total average kinetic energy is KE = (3/2)kT. Here k is the Boltzmann constant and T is the absolute temperature in kelvin. This (3/2) is the source of the 3 that appears in the wavelength formula.

How does the 3 end up under the square root in lambda = h/sqrt(3mkT)?

Start with lambda = h/p and p = sqrt(2 m KE). Put KE = (3/2)kT. Then 2 m KE = 2 m times (3/2)kT = 3 m k T. So p = sqrt(3 m k T) and lambda = h/sqrt(3 m k T). The factor 2 from momentum cancels the (1/2) inside the energy, leaving a clean 3 under the root.

Do I use temperature T directly in the formula, or convert it?

You use the absolute temperature in kelvin. If a problem gives Celsius, first convert: T(K) = T(C) + 273. For a 'thermal' neutron the room-temperature value is about T = 300 K (roughly 27 C). Never put Celsius directly into the formula, and never leave T out; a thermal neutron's speed comes only from temperature.

How is a thermal neutron different from an accelerated electron for this formula?

An electron is charged, so we speed it up with a voltage V and its energy is KE = eV, giving lambda = h/sqrt(2 m e V). A neutron has no charge, so a voltage cannot push it. A neutron gets its speed only from heat, so its energy is (3/2)kT and lambda = h/sqrt(3 m k T). Same idea lambda = h/sqrt(2 m KE), but the source of KE is different.

Why is a slow thermal neutron useful, and does slow mean a longer wavelength?

Yes. Lower temperature means smaller KE, smaller momentum p, and since lambda = h/p a smaller p gives a larger lambda. A thermal neutron at 300 K has a wavelength near 0.15 to 0.18 nm, which is close to the spacing between atoms in a crystal. That is why slow neutrons diffract from crystals, just like the electrons in the Davisson-Germer experiment.

⚠️ The NEET trap
Using KE = kT (or KE = (1/2)kT) and getting lambda = h/sqrt(2mkT).
A thermal neutron moves in 3 dimensions, so KE = (3/2)kT and lambda = h/sqrt(3mkT).
🧠 Three directions of motion put a 3 under the root, not a 2. Count the dimensions before you square-root.

Real NEET questions

2017

The de Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (kelvin) and mass m is:

A · h/sqrt(mkT)
B · h/sqrt(3mkT)
C · 2h/sqrt(3mkT)
D · 2h/sqrt(mkT)
Solution: Step 1: A neutron in thermal equilibrium has average kinetic energy KE = (3/2)kT, from equipartition over 3 directions. Step 2: Momentum p = sqrt(2 m KE) = sqrt(2 m times (3/2)kT) = sqrt(3 m k T). Step 3: de Broglie wavelength lambda = h/p = h/sqrt(3 m k T). This matches option B.

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Frequently asked

What is the formula for the de Broglie wavelength of a thermal neutron?

lambda = h / sqrt(3 m k T), where h is Planck's constant, m is the neutron mass, k is the Boltzmann constant and T is the absolute temperature in kelvin.

What is the approximate de Broglie wavelength of a thermal neutron at room temperature?

At about T = 300 K it is roughly 0.145 nm (about 1.45 angstrom). This is close to atomic spacing in crystals, which makes thermal neutrons good for diffraction.

Why can we not use KE = eV for a neutron?

A neutron has no electric charge, so an accelerating voltage does no work on it. Its kinetic energy comes only from thermal motion, giving KE = (3/2)kT instead of eV.

What value of the Boltzmann constant should I use?

k = 1.38 x 10^-23 J/K. Use the neutron mass m = 1.67 x 10^-27 kg and h = 6.63 x 10^-34 J·s for numerical problems.

Does the neutron wavelength increase or decrease if the water is cooled?

It increases. Cooling lowers T, which lowers KE and momentum p, and since lambda = h/p a smaller p gives a larger lambda. Very cold (slow) neutrons have longer wavelengths.