Physics · Laws Of Motion · NEET
No, it is not a real force and no object exerts it. A real force always has a source (gravity from Earth, tension from a string, normal from a surface) and obeys Newton's third law with a reaction. Pseudo force has NO source and NO reaction pair. We only invent it because inside an accelerating (non-inertial) frame the body looks like it accelerates without any real cause. Adding F = ma opposite to the frame's acceleration lets us keep using F = ma inside that frame. In the ground (inertial) frame it does not exist at all.
Think of a bus accelerating forward. By inertia your body wants to stay still, so relative to the bus you get thrown backward. To an observer inside the bus, it feels like a force pushed you backward - opposite to the forward acceleration of the bus. So the rule is: pseudo force = m * a_frame, direction opposite to a_frame. If the vehicle accelerates right, the pseudo force on every object inside is toward the left.
An inertial frame moves at constant velocity (or is at rest) - here Newton's first law holds and you need NO pseudo force. A non-inertial frame is accelerating (speeding up, slowing down, or turning) - here you MUST add a pseudo force for Newton's laws to work. NEET trap: a lift moving with UNIFORM velocity is still inertial (no pseudo force), only an accelerating lift is non-inertial. This is exactly the 2024 coin-in-elevator PYQ.
You never HAVE to use pseudo force. Any problem can be solved from the ground (inertial) frame using only real forces and the real acceleration. Pseudo force is just a shortcut that makes the body appear in equilibrium inside the accelerating frame, which is often faster for bob-in-vehicle and wedge problems. Rule: choose the vehicle frame and ADD pseudo force = ma, OR choose the ground frame and DO NOT add it. Never mix the two.
Direction depends on the frame's acceleration, not on which way it moves. If the lift accelerates UPWARD (a upward), the pseudo force on you is DOWNWARD, so you feel heavier (apparent weight m(g + a)). If the lift accelerates DOWNWARD, the pseudo force is UPWARD, so you feel lighter (apparent weight m(g - a)). A lift moving up at constant speed has zero acceleration, so no pseudo force and normal weight.
A bob is suspended by a light string from the roof of a truck. The truck, initially stationary, suddenly moves to the right with acceleration a. The pendulum will tilt:
A block of mass m is placed on a smooth inclined wedge ABC of inclination theta. The wedge is given a horizontal acceleration 'a' towards the right. The relation between a and theta for the block to remain stationary on the wedge is:
A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t1 if the elevator is at rest, and in time t2 if the elevator is moving uniformly. Then:
Try the real previous-year questions from this chapter — each with the answer and a full solution.
F_pseudo = m * a, where m is the mass of the body and a is the acceleration of the non-inertial frame. Its direction is exactly opposite to the frame's acceleration.
Yes. When you sit in a rotating (accelerating) frame, the outward centrifugal force m*v^2/r is a pseudo force. It appears only in the rotating frame; in the ground frame only the inward centripetal force is real.
Whenever the frame is inertial - at rest or moving with constant velocity. A lift or car moving at steady speed has zero acceleration, so the pseudo force is zero and objects behave normally.
No. Newton's third law applies only to real forces. Since pseudo force has no physical source, it has no reaction pair - this is one clear way to tell it is fictitious.
Add ma opposite to the vehicle's acceleration, then treat the bob as in equilibrium. Balancing gives tan(theta) = a/g, where theta is the tilt from the vertical. This directly solves the NEET 2024 truck bob PYQ.