What is Hooke's Law? Statement and Limitations

Physics · Mechanical Properties Of Solids · NEET

Hooke's law says that for small deformations, the stress in a body is directly proportional to the strain. In formula form, stress = k x strain, where k is the modulus of elasticity (a constant for each material). Memory hook: "Small stretch, straight line" - Hooke's law only works on the straight (linear) part of the stress-strain graph, up to the proportional limit.
Stress-Strain Graph: Hooke's Law region onlyStrain (no units)Stress (N/m^2)A: Proportional limitStraight lineHooke's law holdsB: Elastic limit (still elastic,but NOT proportional)slope of OA = k = modulus of elasticity
Only the straight part OA obeys Hooke's law (stress proportional to strain). Its slope is k, the modulus of elasticity. Point A is the proportional limit; the body stays elastic a bit further to B (elastic limit), but stress and strain are no longer proportional there.

Your doubts, answered

Is Hooke's law 'stress proportional to strain' or 'force proportional to extension'? Which one does NEET use?

Both are Hooke's law, but NEET (Class 11 NCERT) states it as: stress is directly proportional to strain, so stress = k x strain. The spring version (F = kx, force proportional to extension) is a special case of the same idea. In the NCERT statement, k is the modulus of elasticity. In the spring version, k is the spring constant. Read the question: if it gives stress and strain, use stress = k x strain; if it gives force and extension of a spring, use F = kx.

What exactly is k in Hooke's law?

k is the proportionality constant called the modulus of elasticity. It equals stress divided by strain (k = stress/strain) and is a fixed property of the material, not of the sample size. Its SI unit is the same as stress, N/m^2 (pascal), because strain has no units. Different types of deformation give different moduli: Young's modulus (Y) for length change, shear modulus (G) for shape change, and bulk modulus (B) for volume change.

Up to which point is Hooke's law valid - proportional limit or elastic limit?

Hooke's law is valid only up to the proportional limit (point A on the stress-strain curve), where the graph is a straight line. Beyond A, the body may still be elastic (returns to shape) up to the elastic limit / yield point B, but stress and strain are NO LONGER proportional there. So: elastic behaviour lasts longer than Hooke's law. A body can obey elasticity but disobey Hooke's law in the region between proportional limit and elastic limit.

Does Hooke's law apply to rubber?

No, not over most of its range. NCERT points out that elastic materials like rubber and the elastic tissue of the aorta can be stretched a lot and still return to shape (they are elastic), but their stress-strain graph is a curve, not a straight line. Since stress is not proportional to strain, they do NOT obey Hooke's law over most of the region. Hooke's law is only for small deformations of ordinary solids like metals.

Why is Hooke's law called an 'empirical' law?

NCERT calls Hooke's law an empirical law, meaning it is based on experiment and observation, not derived from a deeper theory. It works well for many materials for small strains but it is an approximation - it fails for large deformations and for materials like rubber. This is a common one-word NTA fill-in-the-blank: Hooke's law is empirical and holds only for small deformations.

⚠️ The NEET trap
Hooke's law is valid up to the elastic limit (yield point).
Hooke's law is valid only up to the proportional limit, on the straight-line part of the graph. Elastic behaviour continues a little beyond it, but stress and strain stop being proportional there.
🧠 Elastic limit is farther than the proportional limit. A body can still be elastic yet break Hooke's law. Never equate 'obeys Hooke's law' with 'is elastic.'

Real NEET questions

2024

The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young's modulus respectively are 8 x 10^8 N/m^2 and 2 x 10^11 N/m^2, is

A · 0.4 mm
B · 40 mm
C · 8 mm
D · 4 mm
Solution: Step 1: Young's modulus formula: Y = stress / strain = stress / (delta L / L). Rearrange: delta L = (stress x L) / Y. Step 2: The maximum elongation happens at the maximum stress the wire can take while still elastic, which is the elastic limit. So use stress = 8 x 10^8 N/m^2. Step 3: Substitute values: delta L = (8 x 10^8 x 1) / (2 x 10^11). Step 4: delta L = (8 / 2) x 10^(8-11) = 4 x 10^-3 m = 4 mm. Answer: D. Note: this uses Y = stress/strain, which is Hooke's law written for stretching.

Solved Mechanical Properties Of Solids NEET PYQs

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Frequently asked

What is the statement of Hooke's law?

For small deformations, the stress in a body is directly proportional to the strain produced in it. In symbols: stress is proportional to strain, so stress = k x strain, where k is the modulus of elasticity of the material.

What is the SI unit of the constant k in Hooke's law?

The unit of k (modulus of elasticity) is N/m^2, also called the pascal (Pa). This is because k = stress/strain, stress has units N/m^2, and strain is a pure number with no units.

Is Hooke's law a fundamental law or an empirical law?

It is an empirical law. It is based on experimental observation and works only as an approximation for small strains; it is not derived from any deeper principle and fails for large deformations.

What are the limitations of Hooke's law?

Hooke's law fails for large deformations, so it holds only for small strains up to the proportional limit. It does not apply to elastomers like rubber whose stress-strain graph is curved, and beyond the proportional limit stress and strain are no longer proportional.

Does the loaded wire in a NEET numerical always obey Hooke's law?

Only if the applied stress stays within the proportional limit. NEET problems using Y = stress/strain assume Hooke's law holds. If the stress equals the elastic limit, you get the maximum elongation while still elastic, as in the 2024 PYQ.