Focal Length and Radius of Curvature Relation for Mirrors (f = R/2)

Physics · Ray Optics And Optical Instruments · NEET

For any spherical mirror (concave or convex), the focal length is exactly half the radius of curvature: f = R/2. The focus F sits at the midpoint of the line joining the pole P and the centre of curvature C. Memory hook: "Focus is the Half-way house" — F is always halfway between the mirror surface and its centre C.
PFCMf = FPR = CPf = R/2 (F is the midpoint of PC)
A paraxial ray parallel to the axis reflects at M through focus F. Triangle CMF is isosceles (CF = FM), and since M is near pole P, F bisects the pole-to-centre distance PC, giving f = R/2.

Your doubts, answered

Is f = R/2 true for both concave and convex mirrors?

Yes. The relation f = R/2 holds for both mirror types. For a concave mirror, R is negative (centre C is in front, on the same side as the object), so f is also negative. For a convex mirror, R is positive (C is behind the mirror), so f is positive. The magnitude rule |f| = |R|/2 never changes; only the signs flip with the Cartesian sign convention.

Why is focal length exactly half the radius of curvature?

A ray parallel to the principal axis hits the mirror at point M and reflects to cross the axis at focus F. The normal at M passes through the centre of curvature C, so the angle of incidence equals the angle CMF. By the law of reflection and alternate angles, triangle CMF is isosceles with CF = FM. For a small aperture (paraxial ray), M lies very close to the pole P, so FM is almost equal to FP = f and CP = R. Since F bisects CP, we get f = R/2.

Does f = R/2 work for every ray or only paraxial rays?

Only for paraxial rays — rays close to and nearly parallel to the principal axis. For rays far from the axis (a wide aperture), reflected rays cross the axis at different points, causing spherical aberration, and there is no single sharp focus. NEET always assumes paraxial (small-aperture) mirrors, so you can safely use f = R/2 in every numerical.

What signs do f and R take for a concave mirror in NEET?

Using the Cartesian sign convention with light travelling left to right, distances measured against the incident light are negative. For a concave mirror both C and F are in front (real side), so R and f are both negative. Example: a concave mirror of radius of curvature 20 cm has R = -20 cm and f = -10 cm. Watch out: many problems quote the magnitude, and you must attach the minus sign yourself.

Is the f = R/2 rule the same for lenses?

No. f = R/2 is a mirror-only relation. Lenses have two surfaces with radii R1 and R2 and depend on the refractive index through the Lens Maker's Formula: 1/f = (n-1)(1/R1 - 1/R2). Never apply f = R/2 to a lens in NEET — it is a common trap.

How do I find the radius of curvature when the focal length is given?

Just double the focal length: R = 2f. If a concave mirror has f = -15 cm, then R = -30 cm. If a convex mirror has f = +25 cm, then R = +50 cm. Keep the sign of f and it carries over to R automatically.

⚠️ The NEET trap
Writing R = f/2, so a mirror with f = 10 cm is claimed to have R = 5 cm.
The focal length is HALF the radius, so f = R/2 and therefore R = 2f. A mirror with f = 10 cm has R = 20 cm. Focus lies halfway to the centre, so the centre is twice as far as the focus.
🧠 NEET loves mixing up whether R = 2f or f = 2R.

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Frequently asked

Does f = R/2 depend on the medium in which the mirror is kept?

No. Mirror focal length depends only on geometry (reflection), not on the surrounding medium. A concave mirror has the same f in air, water, or oil. This is unlike a lens, whose focal length changes when immersed in a liquid because refraction depends on the relative refractive index.

What is the focal length of a plane mirror using f = R/2?

A plane mirror is a spherical mirror with infinite radius of curvature (R = infinity). So f = R/2 = infinity. That is why a plane mirror cannot converge parallel rays to a real focus — its focus is at infinity, and it always forms a virtual, erect, same-size image.

If two mirrors have radii 30 cm and 60 cm, which has the shorter focal length?

Since f = R/2, the mirror with the smaller radius has the shorter focal length. The 30 cm mirror has f = 15 cm and the 60 cm mirror has f = 30 cm. A shorter focal length means a more strongly curved, more converging (or diverging) mirror.

Can I use f = R/2 directly in the mirror formula?

Yes. First convert the given radius to focal length using f = R/2 (keeping the correct sign), then plug f into the mirror formula 1/v + 1/u = 1/f. NEET numericals often give R and expect you to make this conversion in the first step.