Relation Between Torque and Angular Momentum

Physics · System Of Particles And Rotational Motion · NEET

The torque acting on a particle equals the rate of change of its angular momentum: tau = dL/dt. This is the rotational twin of Newton's second law F = dp/dt, where torque replaces force and angular momentum replaces linear momentum. Memory hook: "Torque twists momentum" - just as force changes linear momentum, torque changes angular momentum over time.
Torque changes Angular Momentum: tau = dL/dtO (origin)rmFp = mvtau = r x FL = r x pdL/dt = tau(rotational F = dp/dt)If tau = 0 then L = constant (conserved)
A particle of mass m at position r has angular momentum L = r x p about O. An external force F gives torque tau = r x F. The relation tau = dL/dt shows torque is the rate of change of L; when torque is zero, L is conserved.

Your doubts, answered

Is torque really the rate of change of angular momentum?

Yes. For a single particle, angular momentum is L = r x p. Differentiating with respect to time: dL/dt = (dr/dt x p) + (r x dp/dt). The first term is v x mv = 0 (a vector crossed with itself is zero). The second term is r x F, which is the torque tau. So dL/dt = tau. This is the exact rotational analogue of Newton's second law F = dp/dt.

What is the difference between tau = dL/dt and tau = I alpha?

They are the same law written differently. tau = dL/dt is the general form and always works. For a rigid body rotating about a fixed axis with a constant moment of inertia I, L = I omega, so dL/dt = I (d omega/dt) = I alpha. So tau = I alpha is just the special case when I stays constant. If I changes (like a spinning skater pulling arms in), you must use tau = dL/dt.

Why does zero torque mean angular momentum stays constant?

If the total external torque is zero, then dL/dt = 0, which means L does not change with time. So L stays constant. This is the conservation of angular momentum. A spinning ice skater, a planet orbiting the Sun, and a diver curling up all keep L fixed because no net external torque acts on them.

For a system of particles, is it total torque or external torque in tau = dL/dt?

Only the external torque matters. Inside a system, internal forces between particles come in action-reaction pairs along the line joining them, so their torques cancel out in total. NCERT states: the time rate of the total angular momentum of a system about a point equals the sum of the external torques about the same point. So dL/dt = tau_external.

Do the torque and angular momentum have to be taken about the same point?

Yes, always. Both tau and L must be measured about the same origin (reference point). If you shift the origin, both quantities change, but the relation tau = dL/dt still holds as long as you use the same point for both. Mixing points gives wrong answers in NEET problems.

⚠️ The NEET trap
Students write tau = I alpha for every rotation problem, even when the moment of inertia I is changing.
The always-valid law is tau = dL/dt. Use tau = I alpha only when I is constant. When I changes (skater pulls arms in, mass moves along a rotating rod), use L = I omega and tau = dL/dt or conservation of L.
🧠 tau = dL/dt is the boss; tau = I alpha is its shortcut for constant I only.

Solved System Of Particles And Rotational Motion NEET PYQs

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Frequently asked

What is the relation between torque and angular momentum?

Torque equals the rate of change of angular momentum: tau = dL/dt. This means torque is what changes the angular momentum of a body over time, exactly as force changes linear momentum (F = dp/dt).

Is tau = dL/dt valid for a system of particles?

Yes, but only the external torque counts. The time rate of change of the total angular momentum of a system equals the sum of the external torques acting on it, because internal torques cancel in action-reaction pairs.

What happens to angular momentum when torque is zero?

When the net external torque is zero, dL/dt = 0, so angular momentum L stays constant. This is the law of conservation of angular momentum, used for spinning skaters, planets, and rotating stools.

How is tau = dL/dt derived?

Start with L = r x p. Differentiate: dL/dt = (v x mv) + (r x F). The first term is zero because v is parallel to mv. The second term r x F is the torque tau. Hence dL/dt = tau.

Why is tau = dL/dt important for NEET?

It is the master equation for rotational dynamics. From it you get tau = I alpha (constant I) and conservation of angular momentum (zero torque). NEET tests both special cases, so understanding the parent relation lets you solve any rotation problem.