Newton's Law of Cooling: Statement, Formula and Graph

Physics · Thermal Properties Of Matter · NEET

Newton's law of cooling says a hot body loses heat at a rate proportional to how much hotter it is than its surroundings. In simple terms: rate of cooling = k (T_body - T_surroundings). Memory hook: "the bigger the temperature gap, the faster it cools" - a very hot cup drops temperature fast at first, then slows down as it gets close to room temperature.
Newton's Law of Cooling: Temperature vs TimeTime (t)TemperatureSurrounding temp (T_surr)steep = fast coolingflatter = slow coolinghot body
The cooling curve is steep at first because the temperature gap with the surroundings is large, then flattens as the body approaches the surrounding temperature (dashed line).

Your doubts, answered

What exactly does Newton's law of cooling state?

It states that the rate of loss of heat (or rate of fall of temperature) of a body is directly proportional to the excess of its temperature over the surroundings, provided this excess is small. As a formula: -dT/dt = k (T - T_surr), where k is a positive constant depending on the body's surface area, nature, and surroundings.

Why does the cooling graph curve and flatten instead of being a straight line?

Because the rate of cooling depends on the temperature gap. When the body is very hot, the gap (T - T_surr) is large, so it cools fast (steep curve). As the body cools, the gap shrinks, so the rate slows down. The temperature approaches the surrounding temperature but never quite reaches it, giving an exponential decay curve that flattens.

Is Newton's law of cooling the same as Stefan-Boltzmann law?

No. Stefan-Boltzmann law (E proportional to T^4) is the exact law for radiation over any temperature range. Newton's law of cooling is an approximation of it that holds only for SMALL temperature differences between the body and its surroundings. For small gaps, the T^4 law reduces to a simple linear form, which is Newton's law.

When can I NOT use Newton's law of cooling?

You cannot use it when the temperature difference between the body and surroundings is large. The law is only a valid approximation for small excess temperatures. For large differences you must use the full Stefan-Boltzmann radiation law.

How is the 'average temperature' trick used in numericals?

For a body cooling from T1 to T2 over a time t, we write (T1 - T2)/t = k[(T1 + T2)/2 - T_surr]. Here (T1+T2)/2 is the average temperature of the body during that interval, used because we approximate the rate over the whole interval. This linear form is the fast way to solve most NEET cooling problems.

⚠️ The NEET trap
Using the starting temperature (or ending temperature) alone in the rate equation instead of the average temperature over the interval.
For an interval, use the AVERAGE body temperature: (T1 - T2)/t = k[(T1+T2)/2 - T_surr]. This is what the standard NEET solution uses.
🧠 Rate over an interval needs the AVERAGE temperature, not the start value.

Real NEET questions

NEET 2016 Phase 2

A body cools from a temperature 3T to 2T in 10 minutes. The surroundings are at temperature T. Assuming Newton's law of cooling holds, the temperature of the body at the end of the next 10 minutes will be:

A · 7T/4
B · 3T/2
C · 4T/3
D · T
Solution: Step 1: Apply the average-temperature form of Newton's law: (change in T)/time = k(average body temp - surroundings). First 10 min, body goes 3T to 2T. (3T - 2T)/10 = k[(3T + 2T)/2 - T] = k(3T/2). So k = 1/15. Step 2: Next 10 min, let final temperature be theta. (2T - theta)/10 = k[(2T + theta)/2 - T] = (1/15)(theta/2). This gives 3(2T - theta) = theta. Step 3: 6T - 3theta = theta, so 6T = 4theta, giving theta = 3T/2. Answer: 3T/2 (option B).

Solved Thermal Properties Of Matter NEET PYQs

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Frequently asked

What is Newton's law of cooling formula?

The rate of cooling equals a constant times the temperature difference: -dT/dt = k(T - T_surr). In interval form for solving problems: (T1 - T2)/t = k[(T1 + T2)/2 - T_surr].

What is the shape of the Newton's law of cooling graph?

A temperature-versus-time graph is an exponential decay curve. It starts steep (fast cooling when the gap is large) and gradually flattens, approaching the surrounding temperature but never crossing it.

What are the conditions for Newton's law of cooling to be valid?

The temperature difference between the body and surroundings must be small, the surroundings must stay at constant temperature, and heat loss must be mainly by radiation and convection under steady conditions.

Is the constant k the same for all bodies?

No. The constant k depends on the surface area, the nature of the surface (emissivity), the mass and specific heat of the body, and the surroundings. A body with larger surface area cools faster.

How is Newton's law of cooling derived from Stefan's law?

Stefan's law gives heat loss proportional to (T^4 - T_surr^4). For a small excess temperature, this expression can be approximated to a form proportional to (T - T_surr), which is exactly Newton's law of cooling.