How a Nerve Impulse is Conducted Along the Axon

Biology · Neural Control and Coordination · NEET

A nerve impulse is conducted along the axon as a wave of depolarisation. When one point on the membrane depolarises (Na+ rushes in), it makes a tiny electric current that flows to the next point and depolarises it too, so the action potential moves point by point down the axon. Memory hook: the impulse is like a line of falling dominoes, one point knocks over the next, and it never falls backward because the point behind is still resting (refractory).
Impulse conduction along the axon (one-way wave)refractoryfiring nownext: firesjust firedNa+ in (+ inside)still resting (-)local currentblockedrestingresting axonImpulse travels this way only (never backward)
A firing point (Na+ in) sends a local current forward that makes the next resting point fire, while the point behind is refractory and cannot fire, so the impulse moves in only one direction.

Your doubts, answered

Does one action potential travel the whole length of the axon, or is a fresh one made at each point?

A fresh one is made at each point. The action potential does not physically slide along like a marble. When a site depolarises, the small local current it creates depolarises the next site, which then generates its OWN action potential. So conduction is a chain of new action potentials, each one regenerated at the next spot. This is why the signal does not fade with distance.

Why does a nerve impulse move only forward and not backward?

The region just behind the impulse is in the refractory phase. After a point fires, its Na+ channels are briefly inactivated and it cannot be re-stimulated for a short time. So the local current can only excite the region ahead (which is still at resting potential), not the region behind. This gives the impulse a one-way direction along the axon. This exact idea was tested in NEET (refractory phase stops backward movement).

What actually pushes the impulse to the next part of the axon?

A local (circuit) current. At the depolarised point the inside becomes positive while the neighbouring point is still negative inside. Because there is now a charge difference between the two neighbouring points, a tiny current flows between them. This current depolarises the next point up to threshold, so it fires. Then that point does the same to the point after it, and so on down the axon.

Does the impulse get weaker as it travels down a long axon?

No. Because a brand-new full-strength action potential is regenerated at every point, the impulse arrives at the axon terminal just as strong as it started. This is the all-or-none property: the size of the impulse does not shrink over distance. Only its speed differs between myelinated and non-myelinated fibres.

How is conduction different in a myelinated axon?

In a non-myelinated axon the impulse moves smoothly, point after point, which is slower. In a myelinated axon the myelin insulates the membrane, so the impulse jumps from one Node of Ranvier to the next (this is saltatory conduction). Fewer points need to fire, so the impulse travels much faster. The step-by-step mechanism (Na+ in, local current, next point fires) is the same, just at the nodes.

⚠️ The NEET trap
The same single action potential physically slides all the way from one end of the axon to the other.
A new action potential is regenerated at each successive point along the axon; the impulse is a self-propagating wave, not one moving object.
🧠 NTA loves the word 'propagated'. If a statement says the impulse is regenerated point-by-point it is correct; if it says the same potential moves unchanged and can go both ways, it is the trap.

Real NEET questions

NEET 2016 (repeated 2017, 2019, 2020, 2021, 2023)

Which of the following statements is not correct?

A · An action potential in an axon does not move backward because the segment behind is in a refractory phase
B · Depolarisation of hair cells of cochlea results in the opening of the mechanically gated potassium-ion channels
C · Rods are very sensitive and contribute to daylight vision
D · In the knee-jerk reflex, stimulus is the stretching of muscle and response is its contraction
Solution: Option (a) correctly states the conduction rule for the axon: the impulse cannot move backward because the segment behind is in the refractory phase, so the impulse travels one way only. The wrong statement is (c) rods contribute to daylight vision, because rods work in dim light and cones handle bright/daylight vision. Note how the exam directly rewards knowing WHY conduction is unidirectional (refractory phase behind the impulse).

Solved Neural Control and Coordination NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

See all 11 Neural Control and Coordination NEET PYQs ›
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Frequently asked

In one line, how is a nerve impulse conducted along the axon?

As a moving wave of depolarisation: Na+ enters at one point, the local current it makes depolarises the next point, and a new action potential fires there, repeating down the axon.

Is nerve impulse conduction the same as an action potential?

Closely linked but not identical. An action potential is the electrical event at one point (depolarisation then repolarisation). Conduction is that action potential being regenerated at point after point so the signal travels along the axon.

Why can the impulse not fade over a long axon?

Because a full-strength action potential is freshly generated at every point (all-or-none). Energy is added at each step, so the impulse arrives at the end as strong as it began.

Which ion movement starts the conduction at each point?

Sodium (Na+) influx. Na+ rushing in reverses the membrane to positive inside (depolarisation), which creates the local current that triggers the next point.

What is the role of the refractory phase in conduction?

It makes conduction one-directional. The point that just fired cannot fire again for a moment, so the impulse can only move to the resting region ahead, never backward.