Electrophilic Substitution of Phenol: Nitration, Bromination and Why -OH Activates the Ring

Chemistry · Alcohols, Phenols And Ethers · NEET

The -OH group in phenol has a lone pair of electrons. This lone pair moves into the benzene ring and makes the ring electron-rich. So phenol reacts much faster than benzene with electrophiles, and the new group goes to the ortho and para positions. Memory hook: "OH feeds the ring, so it eats electrophiles fast at o and p."
Phenol: -OH lone pair feeds the ring (o/p directing)OHlone pairpushes inoopelectron-rich at o & pBr2 / water(no catalyst)OHBrBrBr2,4,6-tribromophenol (white ppt)Key rule+R (donate) > -I (pull)so ring is ACTIVATEDfaster than benzene,attacks at o & p
The -OH lone pair donates electron density into the ring (+R effect), building up charge at the ortho and para carbons. This activates phenol so it reacts faster than benzene; for example bromine water needs no catalyst and gives 2,4,6-tribromophenol.

Your doubts, answered

Why does the -OH group activate the ring instead of pulling electrons away?

Oxygen is electronegative and does pull some electrons (-I effect). But oxygen also has lone pairs. One lone pair overlaps with the ring's pi system and pushes electron density INTO the ring (+R or +M effect). For phenol, this electron donation (+R) is stronger than the electron pull (-I). So the net effect is that the ring becomes electron-rich, which is called 'activated'. An electron-rich ring attracts electrophiles more strongly, so reaction is faster. This is why it matters for NEET: they test whether you know +R beats -I here.

Why does the new group go to ortho and para, not meta?

When you draw the resonance structures of phenol, the negative charge (extra electron density) lands on the ortho and para carbons, not the meta carbons. Electrophiles attack where electrons are, so they attack ortho and para. So phenol is an 'ortho/para director'. Remember: the -OH lone pair can only push charge to o and p positions, never to meta.

Why is phenol so much more reactive than benzene?

Benzene has an even ring and no extra electron push. Phenol's -OH keeps feeding electrons into the ring. More electron density means the ring grabs electrophiles much faster. Real proof: phenol reacts with bromine WATER at room temperature and needs NO catalyst (no FeBr3), while benzene needs a Lewis acid catalyst and stronger conditions. If a NEET question says 'reacts with bromine water without a catalyst', the answer is usually phenol or aniline (both activated).

Why does phenol give 2,4,6-tribromophenol with bromine water but only monobromophenol in CS2 or CHCl3?

Bromine water is a polar solvent. In water, phenol ionises a little to phenoxide, which is even more activated, so all three free positions (2 ortho + 1 para) get brominated, giving a white precipitate of 2,4,6-tribromophenol. In a non-polar solvent like CS2 or CHCl3 at low temperature (273 K), phenol stays neutral and less reactive, so only ONE bromine goes in, mainly at para, giving p-bromophenol. NEET loves testing this solvent difference.

What does dilute HNO3 give and what does concentrated HNO3/H2SO4 give?

With DILUTE nitric acid at low temperature, phenol gives a mixture of o-nitrophenol and p-nitrophenol (only one -NO2 goes in). With CONCENTRATED HNO3 plus concentrated H2SO4, all three positions react and you get 2,4,6-trinitrophenol, called picric acid. So: dilute = mono (o + p mix); concentrated = tri (picric acid). Do not mix these two up in the exam.

How do you separate ortho-nitrophenol from para-nitrophenol?

o-Nitrophenol has the -OH and -NO2 next to each other, so it forms an INTRAmolecular hydrogen bond (a ring inside one molecule, called chelation). This makes it more volatile (steam-volatile, lower boiling). p-Nitrophenol has the groups far apart, so it forms INTERmolecular hydrogen bonds between molecules, making it less volatile (higher boiling). Because their volatilities/boiling points differ, they can be separated by steam distillation or fractional distillation. NEET has asked both answers in different years, so read the exact wording of the options given.

⚠️ The NEET trap
Because -OH is on an electronegative oxygen, students think phenol is deactivated and directs the new group to meta.
The oxygen lone pair donates into the ring by +R, which outweighs the -I pull. So phenol is ACTIVATED and directs to ortho and para, never meta.
🧠 Lone pair wins: +R beats -I, so phenol is o/p directing and reacts faster than benzene.

Real NEET questions

NEET 2017

The most suitable method of separation of a 1:1 mixture of ortho- and para-nitrophenols is

A · Sublimation
B · Chromatography
C · Crystallisation
D · Steam distillation
Solution: In o-nitrophenol the -OH and -NO2 are next to each other, so it forms an intramolecular hydrogen bond (chelation). This makes it volatile and steam-volatile. In p-nitrophenol the groups are far apart, so it forms intermolecular hydrogen bonds and is less volatile. Steam distillation carries over the o-isomer while the p-isomer stays behind, so the answer is (D) Steam distillation.
NEET 2026

In the reaction C6H5OH + conc. HNO3 / conc. H2SO4 -> X + Y, where X and Y are o-nitrophenol and p-nitrophenol, the suitable method to separate X and Y is:

A · Fractional distillation
B · Sublimation
C · Differential extraction
D · Continuous extraction
Solution: Nitration of phenol gives o- and p-nitrophenol. o-Nitrophenol has intramolecular H-bonding (more volatile, b.p. ~222 C) while p-nitrophenol has intermolecular H-bonding (less volatile, b.p. ~238 C). Because their boiling points differ enough, the two can be separated by fractional distillation. Answer: (A). Note: in NEET 2017 the same idea was tested with 'steam distillation' as the correct choice, so always pick from the exact options given.
NEET 2018

In the reaction C6H5OH + CHCl3 + NaOH -> salicylaldehyde, the electrophile involved is

A · Dichloromethyl anion (CHCl2 minus)
B · Formyl cation (+CHO)
C · Dichloromethyl cation (+CHCl2)
D · Dichlorocarbene (:CCl2)
Solution: This is the Reimer-Tiemann reaction. CHCl3 reacts with NaOH to form the trichloromethyl anion, which loses Cl- to give the neutral but electron-poor dichlorocarbene :CCl2. This carbene is the electrophile that attacks the electron-rich ortho carbon of the phenoxide ring. After hydrolysis a -CHO group forms, giving salicylaldehyde. Answer: (D).

Solved Alcohols, Phenols And Ethers NEET PYQs

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Frequently asked

Is phenol more reactive than benzene toward electrophilic substitution?

Yes. The -OH lone pair donates electrons into the ring (+R effect), making the ring electron-rich. An electron-rich ring attracts electrophiles faster, so phenol reacts much faster than benzene and often needs no catalyst.

Does phenol direct to ortho/para or meta?

Ortho and para. The resonance of the -OH lone pair places extra electron density on the ortho and para carbons, so electrophiles attack there. Phenol never directs to meta.

What product forms when phenol reacts with bromine water?

A white precipitate of 2,4,6-tribromophenol forms, with no catalyst needed, because the polar aqueous medium makes phenol very reactive. In a non-polar solvent like CS2 at low temperature, only p-bromophenol forms.

What is the difference between dilute and concentrated HNO3 on phenol?

Dilute HNO3 gives a mono-nitration mixture of o- and p-nitrophenol. Concentrated HNO3 with concentrated H2SO4 gives 2,4,6-trinitrophenol (picric acid).

Why can o-nitrophenol and p-nitrophenol be separated by distillation?

o-Nitrophenol has intramolecular H-bonding, so it is more volatile. p-Nitrophenol has intermolecular H-bonding, so it is less volatile. This difference in volatility/boiling point allows separation by steam or fractional distillation.