Identify the correct reagents that would bring about the following transformation (an alkene converted, via the anti-Markovnikov primary alcohol, to an aldehyde):
Answer: (A) (A) (i) , (ii) /, (iii) PCC. \textbf{Answer:} (A) (i) , (ii) /, (iii) PCC \textbf{Solution:} Hydroboration-oxidation ( then /) adds water across the double bond with anti-Markovnikov regiochemistry, giving the primary alcohol .

- A.(A) (i) , (ii) /, (iii) PCC✓
- B.(B) (i) , (ii) /, (iii) alk. , (iv)
- C.(C) (i) /, (ii) PCC
- D.(D) /
Correct Answer
(A) (A) (i) , (ii) /, (iii) PCC
Solution & Explanation
\textbf{Answer:} (A) (i) , (ii) /, (iii) PCC \textbf{Solution:} Hydroboration-oxidation ( then /) adds water across the double bond with anti-Markovnikov regiochemistry, giving the primary alcohol . PCC (pyridinium chlorochromate) is a mild oxidant that oxidises the 1 alcohol only as far as the aldehyde, without over-oxidation to the carboxylic acid. Option (B) would oxidise further () to the acid; options (C) and (D) give the wrong (Markovnikov) alcohol or no oxidation. Hence (A).
