Order of Dipole Moment: NH3, H2S, H2O, HF (with NEET Tricks)

Chemistry · Chemical Bonding · NEET

The standard order of dipole moment is HF (1.91 D) > H2O (1.85 D) > NH3 (1.47 D) > H2S (0.97 D). It is decided by two things: how different the atoms are in electronegativity, and the shape of the molecule. Memory hook: "Fluorine pulls hardest, so HF wins" — going down the list, the pull gets weaker and the dipole drops.
Dipole Moment Order (Debye)More electronegativity difference + better shape = larger dipoleHF1.91 DF pulls hardestH2O1.85 Dbent 104.5°NH31.47 DH2S0.97 DHF > H2O > NH3 > H2Shighlow
Dipole moment falls from HF to H2S as the electronegativity difference with hydrogen decreases (F > O > N > S); molecular shape gives HF a slight edge over H2O.

Your doubts, answered

What is the correct order of dipole moment for HF, H2O, NH3 and H2S?

HF > H2O > NH3 > H2S. In Debye units: HF ≈ 1.91 D, H2O ≈ 1.85 D, NH3 ≈ 1.47 D, H2S ≈ 0.97 D. Two things set this order — the electronegativity difference between the atoms, and the molecule's shape. HF has the biggest electronegativity gap (F is the most electronegative atom), so it has the largest dipole.

Why does HF have the highest dipole moment?

Because fluorine is the most electronegative element. In HF the shared electron pair is pulled strongly toward F, creating a large charge separation. Also, HF has only one bond, so there is no cancelling of dipoles from other bonds. Big pull + no cancellation = highest dipole moment.

Why does H2S have the lowest dipole moment here?

Sulfur is much less electronegative than oxygen, nitrogen or fluorine. So the S–H bonds are only weakly polar. On top of that, the H–S–H angle is small (about 92°), so the bond dipoles do not add up strongly. Weak bond polarity plus poor geometry gives H2S the smallest dipole (≈ 0.97 D).

Is water or HF higher in dipole moment?

HF is slightly higher (1.91 D) than H2O (1.85 D). Even though water has two O–H bonds, its bent shape at 104.5° means the two bond dipoles partly cancel. HF has just one very polar H–F bond with nothing to cancel it, so it edges ahead. Both are very close, so remember HF just above H2O.

Why is the dipole moment of NH3 more than NF3?

This is a favourite NEET trap. In NH3 the lone-pair dipole points the same way as the sum of the N–H bond dipoles, so they add up (μ ≈ 1.47 D). In NF3 the N–F bond dipoles point toward F, which is opposite to the lone-pair dipole, so they partly cancel (μ ≈ 0.24 D). So NH3 > NF3 even though F is more electronegative than H.

How do I decide dipole moment order fast in the exam?

Step 1: If the molecule is symmetric (like BF3, CO2, CH4, BeF2), its dipole is zero — put it last. Step 2: For the rest, larger electronegativity difference usually means larger dipole. Step 3: If shapes are similar, use electronegativity of the central/other atom. For hydrides: HF > H2O > NH3 > H2S follows falling electronegativity difference.

⚠️ The NEET trap
NF3 has a higher dipole moment than NH3 because fluorine is more electronegative than hydrogen.
NH3 has a higher dipole moment (≈1.47 D) than NF3 (≈0.24 D). In NH3 the lone-pair dipole adds to the bond dipoles; in NF3 it opposes them and cancels most of it.
🧠 Electronegativity alone does not decide dipole moment — the direction of the lone-pair dipole can add or subtract. Always draw the vectors, do not just compare electronegativity.

Real NEET questions

2023

The correct order of dipole moments for molecules NH3, H2S, CH4 and HF, is:

A · NH3 > HF > CH4 > H2S
B · HF > NH3 > H2S > CH4
C · CH4 > H2S > NH3 > HF
D · H2S > NH3 > HF > CH4
Solution: CH4 is tetrahedral and symmetric, so its dipole moment is zero (put it last). For the polar ones, larger electronegativity difference and better geometry give larger dipole: HF (≈1.91 D) > NH3 (≈1.47 D) > H2S (≈0.97 D) > CH4 (0). So the order is HF > NH3 > H2S > CH4.
2019

Which of the following is the correct order of dipole moment?

A · NH3 < BF3 < NF3 < H2O
B · BF3 < NF3 < NH3 < H2O
C · BF3 < NH3 < NF3 < H2O
D · H2O < NF3 < NH3 < BF3
Solution: BF3 is trigonal planar and symmetric, so μ = 0 (smallest). In NF3 the bond dipoles oppose the lone-pair dipole (low μ), while in NH3 they reinforce it (higher μ). H2O (bent, 104.5°) has the largest μ (1.85 D). So BF3 < NF3 < NH3 < H2O.
2025

Identify the correct order for dipole moment: H2O > NH3 > CHCl3.

A · Correct
B · Incorrect — order should be reversed
C · Incorrect — NH3 is highest
D · Incorrect — CHCl3 is highest
Solution: The order H2O (1.85 D) > NH3 (1.47 D) > CHCl3 (≈1.04 D) is correct. Water's high electronegativity difference and bent shape give it the largest dipole; CHCl3 has three C–Cl dipoles that partly oppose the C–H dipole, lowering its net value.

Solved Chemical Bonding NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

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Frequently asked

What is the memory order for dipole moment of hydrides?

HF > H2O > NH3 > H2S. Remember it as electronegativity falling: F > O > N > S. The bigger the electronegativity gap with hydrogen, the bigger the dipole (with a small shape correction for HF vs H2O).

What are the dipole moment values in Debye?

HF ≈ 1.91 D, H2O ≈ 1.85 D, NH3 ≈ 1.47 D, H2S ≈ 0.97 D. The Debye (D) is the unit used for dipole moment; 1 D = 3.336 × 10⁻³⁰ C·m.

Why does molecular shape matter for dipole moment?

Dipole moment is the vector sum of all bond dipoles. If the shape is symmetric (linear, trigonal planar, tetrahedral), the bond dipoles cancel and the net dipole is zero. If the shape is bent or pyramidal, they do not fully cancel, so there is a net dipole.

Does a lone pair affect dipole moment?

Yes. A lone pair has its own dipole. In NH3 and H2O it points in a direction that adds to the bond dipoles, raising the value. In NF3 it points opposite to the bond dipoles, lowering the value. This is why NH3 > NF3.

Why is this concept important for NEET?

NTA asks 'correct order of dipole moment' almost every year (2019, 2023, 2024, 2025). One or two marks are nearly guaranteed if you know the hydride order plus the NH3 vs NF3 trap and which molecules are zero.