NEET 2025 · ChemistryPrevious Year Question

Match List-I with List-II. List-I: A. $XeO X_{3}$ ; B. $XeF X_{2}$ ; C. $XeOF X_{4}$ ; D. $XeF X_{6}$ List-II: I. $s p^{3} d$ ; linear; II. $s p^{3}$ ; pyramidal; III. $s p^{3} d^{3}$ ; distorted octahedral; IV. $s p^{3} d^{2}$ ; square pyramidal Choose the correct answer from the options given below:

Answer: (C) A-II, B-I, C-IV, D-III. \textbf{Answer:} (C) A-II, B-I, C-IV, D-III \textbf{Solution:} $XeO X_{3}$ is $s p^{3}$ trigonal-pyramidal (3 bond pairs + 1 lone pair); $XeF X_{2}$ is $s p^{3} d$ linear (3 lone pairs, $A B 2 E 3$ ); $XeOF X_{4}$ is $s p^{3} d^{2}$ square pyramidal ( $A B 5 E$ ); $XeF X_{6}$ is $s p^{3} d^{3}$ distorted octahedral ( $A B 6 E$ ).

A.A-IV, B-II, C-III, D-I
B.A-IV, B-II, C-I, D-III
C.A-II, B-I, C-IV, D-III✓
D.A-II, B-I, C-III, D-IV

Correct Answer

Solution & Explanation

\textbf{Answer:} (C) A-II, B-I, C-IV, D-III \textbf{Solution:} $XeO X_{3}$ is $s p^{3}$ trigonal-pyramidal (3 bond pairs + 1 lone pair); $XeF X_{2}$ is $s p^{3} d$ linear (3 lone pairs, $A B 2 E 3$ ); $XeOF X_{4}$ is $s p^{3} d^{2}$ square pyramidal ( $A B 5 E$ ); $XeF X_{6}$ is $s p^{3} d^{3}$ distorted octahedral ( $A B 6 E$ ). Hence A-II, B-I, C-IV, D-III.

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Match List-I with List-II. List-I: A. XeOX3​; B. XeFX2​; C. XeOFX4​; D. XeFX6​ List-II: I. sp3d; linear; II. sp3; pyramidal; III. sp3d3; distorted octahedral; IV. sp3d2; square pyramidal Choose the correct answer from the options given below:

Solution & Explanation

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