Main Postulates of VSEPR Theory (Explained Simply)

Chemistry · Chemical Bonding · NEET

VSEPR theory says the electron pairs around a central atom push each other away and arrange themselves as far apart as possible, and this arrangement decides the molecule's shape. A lone pair takes more space and pushes harder than a bond pair, so the repulsion order is lone pair-lone pair > lone pair-bond pair > bond pair-bond pair. Memory hook: "VSEPR = electron pairs hate each other, and lonely (lone) pairs push the hardest."
VSEPR: electron pairs spread out; lone pairs push moreCH4C4 bp, 0 lp109.5 degNH3Nlp3 bp, 1 lp107 degH2OOlplp2 bp, 2 lp104.5 deg
More lone pairs mean stronger repulsion, so the bond angle shrinks: CH4 (109.5 degrees, 0 lone pairs) > NH3 (107 degrees, 1 lone pair) > H2O (104.5 degrees, 2 lone pairs). This shows the VSEPR postulate lp-lp > lp-bp > bp-bp in action.

Your doubts, answered

What are the main postulates of VSEPR theory in simple words?

There are four key ideas. (1) The shape of a molecule depends on the number of electron pairs (bonding and non-bonding) around the central atom. (2) These electron pairs repel each other because they are all negative, so they move as far apart as possible to keep repulsion low. (3) A lone pair (non-bonding pair) takes up more space than a bond pair, so lone pairs repel more strongly. (4) The repulsion order is lone pair-lone pair > lone pair-bond pair > bond pair-bond pair. This is exactly what NEET asks, so learn this order by heart.

Why do lone pairs repel more than bond pairs?

A bond pair is shared between two atoms, so it is pulled by two nuclei and held tightly in the space between them. A lone pair belongs to only one atom, so it is not pulled away and spreads out closer to the central atom, taking up more room. Because it is fatter and closer, a lone pair pushes harder on nearby pairs. This is why lone pairs shrink bond angles.

What is the exact repulsion order I must remember for NEET?

Lone pair-lone pair (lp-lp) > lone pair-bond pair (lp-bp) > bond pair-bond pair (bp-bp). Read it as: two lone pairs repel the most, a lone pair and a bond pair repel medium, two bond pairs repel the least. NEET 2016 asked this order directly and the answer was lp-lp > lp-bp > bp-bp. This single line explains why H2O (104.5 degrees) has a smaller angle than NH3 (107 degrees), which is smaller than CH4 (109.5 degrees).

Does VSEPR count atoms or electron pairs to find the shape?

It counts electron pairs around the central atom, both bond pairs and lone pairs. The total number of electron pairs decides the basic geometry. But the visible shape only uses the positions of the atoms, because lone pairs are invisible. That is why NH3 has 4 electron pairs (tetrahedral geometry) but its shape is called pyramidal, since one corner is a lone pair, not an atom.

What is the difference between geometry and shape in VSEPR?

Geometry (or electron geometry) is the arrangement of ALL electron pairs, including lone pairs. Shape (or molecular shape) is what you actually see using only the atoms. If there are no lone pairs, geometry and shape are the same (like CH4, both tetrahedral). If there are lone pairs, they differ: H2O has tetrahedral geometry but bent shape. NEET options often mix these two words to trap you.

Why does a double or triple bond count as only one electron pair in VSEPR?

VSEPR treats a multiple bond as one region of electron density, so a double bond or triple bond counts as ONE bond pair for deciding shape. For example, CO2 has two double bonds but is treated as two electron regions, giving a linear shape. A multiple bond does repel a bit more than a single bond, but for finding the basic shape you count it as one pair.

⚠️ The NEET trap
Bond pairs repel more than lone pairs, so the order is bp-bp > lp-bp > lp-lp.
Lone pairs repel more than bond pairs. The correct order is lp-lp > lp-bp > bp-bp, because a lone pair is held by only one nucleus and spreads out, taking more space.
🧠 Lonely pairs are grumpy: they push the hardest. lp-lp always sits on top of the order.

Real NEET questions

NEET 2016

Predict the correct order among the following (repulsion between electron pairs as per VSEPR theory):

A · Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
B · Lone pair-lone pair > bond pair-bond pair > lone pair-bond pair
C · Bond pair-bond pair > lone pair-bond pair > lone pair-lone pair
D · Lone pair-bond pair > bond pair-bond pair > lone pair-lone pair
Solution: A core postulate of VSEPR is that lone pairs repel more than bond pairs, because a lone pair is attached to only one nucleus and spreads out closer to the central atom. So the repulsion order is lp-lp > lp-bp > bp-bp. Option A is correct.
NEET 2016

Consider the molecules CH4, NH3 and H2O. Which of the given statements is false?

A · The H-C-H angle in CH4, H-N-H in NH3, and H-O-H in H2O are all greater than 90 degrees.
B · The H-O-H bond angle in H2O is larger than the H-C-H bond angle in CH4.
C · The H-O-H bond angle in H2O is smaller than the H-N-H bond angle in NH3.
D · The H-C-H bond angle in CH4 is larger than the H-N-H bond angle in NH3.
Solution: All three are sp3. As lone pairs increase, lp-bp repulsion increases and the bond angle shrinks: CH4 (109.5 degrees) > NH3 (107 degrees) > H2O (104.5 degrees). So H2O has a SMALLER angle than CH4, which makes statement B false. This is a direct use of the lone-pair repulsion postulate.
NEET 2022

Amongst the following, which one will have maximum 'lone pair-lone pair' electron repulsion?

A · ClF3
B · IF5
C · SF4
D · XeF2
Solution: Lone pair-lone pair repulsion is largest when the central atom has the most lone pairs. XeF2 is AB2E3 with 3 lone pairs on Xe, more than ClF3 (2 lp), SF4 (1 lp) and IF5 (1 lp). So XeF2 has the maximum lp-lp repulsion. This tests the postulate that lone pairs are the strongest repellers.

Solved Chemical Bonding NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

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Frequently asked

Who gave VSEPR theory?

VSEPR (Valence Shell Electron Pair Repulsion) theory was developed mainly by Ronald Gillespie and Ronald Nyholm. For NEET you do not need the history; you need the four postulates and how to use them to predict molecular shape.

Is VSEPR theory the same as hybridisation?

No. VSEPR predicts the shape by counting and repelling electron pairs. Hybridisation explains the bonding using mixed orbitals. They often give the same shape (for example sp3 and 4 electron pairs both give tetrahedral geometry), but they are two different models. NEET may test them together in one option.

Can VSEPR predict bond angles exactly?

No, VSEPR gives the correct order and approximate angles, not exact values. It correctly predicts CH4 > NH3 > H2O for bond angle, but the exact numbers (109.5, 107, 104.5 degrees) come from experiment. VSEPR is a quick tool to compare and predict, which is enough for NEET MCQs.

Does VSEPR work for transition metal complexes?

VSEPR works well for main-group (p-block) molecules. It is less reliable for transition metal complexes because d-electrons and other factors change the shape. For NEET, apply VSEPR to molecules like CH4, NH3, H2O, PCl5, SF6, ClF3 and XeF2, not to coordination complexes.