What Is Resonance? Ozone (O3) and Other Examples

Chemistry · Chemical Bonding · NEET

Resonance happens when one Lewis structure cannot show a molecule correctly, so we draw two or more structures (called canonical or resonance forms). The real molecule is a mix of all of them, called the resonance hybrid, and it is more stable than any single form. Memory hook: "One picture is not enough, so we blend a few." For example, ozone (O3) has two main resonance forms and its two O-O bonds are equal (128 pm), between a single and a double bond.
Resonance of Ozone (O3)OOOForm IOOOForm IIOOOHybridTwo canonical forms blend into one real hybrid.Both O-O bonds become equal: 128 pm (single 148, double 121).Double-headed arrow means resonance, NOT equilibrium.
Ozone (O3) has two canonical Lewis forms (double bond on either side). The real molecule is their resonance hybrid, so both O-O bonds are equal at 128 pm, between a single (148 pm) and a double (121 pm) bond. The double-headed arrow shows resonance, not equilibrium.

Your doubts, answered

What exactly is resonance in simple words?

Resonance means one Lewis structure is not enough to show a molecule correctly. So we draw two or more valid structures. Each one is called a canonical form or resonance form. The true molecule is not any single form. It is a blend of all of them, called the resonance hybrid. NCERT says: whenever a single Lewis structure cannot describe a molecule accurately, a number of structures with similar energy, same positions of nuclei, and same bonding and non-bonding electron pairs are taken together as the canonical forms.

How many resonance structures does ozone (O3) have?

Ozone has two main resonance (canonical) structures. In one form the double bond is on the left O-O and the single bond on the right. In the other form they swap. This is important for NEET: the answer is TWO, not three. NEET 2024 used exactly this trap. The two forms blend into one resonance hybrid, so both oxygen-oxygen bonds become equal.

Why does ozone show resonance? What is the proof?

A single Lewis structure of O3 shows one O-O single bond and one O=O double bond. A normal single O-O bond is 148 pm and a double O=O bond is 121 pm. But experiments show both bonds in O3 are equal, at 128 pm. This is between a single and a double bond. One Lewis structure cannot explain equal bonds, so we need resonance. The real O3 is a hybrid of the two forms.

Are canonical (resonance) forms real? Do they really exist?

No. This is a very common NEET trap. The canonical forms have NO real existence. The molecule does not spend part of its time in one form and part in another form. The molecule has ONE single real structure, which is the resonance hybrid. The separate forms are only drawings we use because one Lewis structure is not enough. Resonance is shown by a double-headed arrow, not an equilibrium arrow.

How many resonance structures does the carbonate ion CO3 2- have?

The carbonate ion CO3 2- has THREE equivalent resonance (canonical) structures. In each form, the C=O double bond is on a different oxygen, and the other two are single C-O bonds. Because all three forms are equal, all three carbon-oxygen bonds become the same length in the real ion. NEET 2024 tested this: three canonical forms for CO3 2- is a correct statement.

Does resonance make a molecule more stable or less stable?

Resonance makes a molecule MORE stable. NCERT states clearly: resonance stabilizes the molecule because the energy of the resonance hybrid is lower than the energy of any single canonical structure. This extra stability is called resonance energy. Resonance also averages the bond characters, so bonds that look different in single structures become equal in the real molecule.

⚠️ The NEET trap
Ozone (O3) has three resonance structures, just like CO3 2-.
Ozone has only TWO main resonance structures. It is the carbonate ion CO3 2- that has three equivalent canonical forms. NEET 2024 put both statements side by side to catch students who memorised only one number.
🧠 O3 has two Os on the sides, so two forms. CO3 2- has three Os, so three forms. Match the count to the terminal atoms.

Real NEET questions

NEET 2024

Identify the correct answer.

A · BF3 has non-zero dipole moment
B · Dipole moment of NF3 is greater than that of NH3
C · Three canonical (resonance) forms can be drawn for CO3 2- ion
D · Three resonance structures can be drawn for ozone (O3)
Solution: Option C is correct. The carbonate ion CO3 2- has three equal canonical forms, with the C=O double bond on a different oxygen each time, so all three C-O bonds are equal. Option A is wrong: BF3 is trigonal planar and symmetric, so its dipole moment is zero. Option B is wrong: in NH3 the lone-pair moment and bond moments add up, giving a higher dipole moment than NF3 where they oppose, so NH3 > NF3. Option D is wrong: ozone has only two main resonance structures, not three. This is the key resonance trap.
NEET 2026

For the ozone (O3) Lewis structure where the central O atom (1) is doubly bonded to one terminal O atom (2) and singly bonded to the other terminal O atom (3), the correct formal charges on the oxygen atoms numbered 2, 1 and 3 respectively are:

A · -1, 0, +1
B · 0, +1, -1
C · 0, 0, 0
D · +1, 0, -1
Solution: Use Formal Charge = V - L - (1/2)S, where V = valence electrons (6 for O), L = lone-pair electrons, S = shared (bonding) electrons. Terminal O (atom 2, double bonded, 4 lone-pair electrons): 6 - 4 - (1/2)(4) = 0. Central O (atom 1, one double + one single bond, 2 lone-pair electrons): 6 - 2 - (1/2)(6) = +1. Terminal O (atom 3, single bonded, 6 lone-pair electrons): 6 - 6 - (1/2)(2) = -1. So the answer is 0, +1, -1. This is why a single ozone structure has charges, and resonance is needed to explain the equal bonds.
NEET 2016 Phase 2 / 2017

Which of the following pairs of ions is isoelectronic and isostructural?

A · CO3 2-, NO3 -
B · ClO3 -, CO3 2-
C · SO3 2-, NO3 -
D · ClO3 -, SO3 2-
Solution: Option A is correct. Both CO3 2- and NO3 - have 24 valence electrons and are trigonal planar with an sp2 central atom, so they are both isoelectronic (same electron count) and isostructural (same shape). Both also show resonance: CO3 2- has three equal canonical forms and NO3 - also has three. The other pairs differ in electron count or shape. This links resonance to symmetric ions where all bonds become equal.

Solved Chemical Bonding NEET PYQs

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Frequently asked

What is the difference between resonance structures and the resonance hybrid?

Resonance structures (canonical forms) are the separate drawings we make when one Lewis structure is not enough. They are only on paper and do not exist by themselves. The resonance hybrid is the ONE real structure of the molecule, a blend of all the canonical forms. Only the hybrid is real.

Which arrow is used for resonance?

Resonance is shown by a double-headed arrow (a single arrow with a head on both ends). This is different from the two half arrows used for equilibrium. Resonance is NOT an equilibrium; the molecule does not move between forms.

What are common examples of resonance for NEET?

The NCERT examples are ozone (O3, two forms), the carbonate ion CO3 2- (three forms), and carbon dioxide CO2. Other frequently asked ions are NO3 - (three forms), NO2, and SO3. Benzene is the classic organic example.

How is resonance energy defined?

Resonance energy is the extra stability a molecule gains from resonance. It is the difference between the energy of the real resonance hybrid and the energy of the most stable single canonical structure. A larger resonance energy means a more stable molecule.

Why do all bonds in a resonating molecule become equal length?

Because resonance averages the bond characters over the whole molecule. In ozone both O-O bonds become 128 pm, between single (148 pm) and double (121 pm). In CO3 2- and NO3 - all three bonds become equal. This equal bond length is direct proof of resonance, and NEET loves asking about it.