Chemistry · General Principles Of Organic Chemistry · NEET
CuO is an oxidising agent that supplies oxygen in a controlled way when heated. It cleanly oxidises the carbon of the compound to CO2 and the hydrogen to H2O. Reactions: C + 2CuO → 2Cu + CO2 and 2H + CuO → Cu + H2O. Plain burning in open air can give soot and lets the CO2 and water escape before you can test them, so CuO inside a closed setup is more reliable.
The CO2 formed is passed into lime water, which is calcium hydroxide solution, Ca(OH)2. It reacts to form insoluble white calcium carbonate: CO2 + Ca(OH)2 → CaCO3 (white) + H2O. The milky or cloudy turbidity is the proof of carbon. No CO2 means no carbon was in the compound.
Anhydrous CuSO4 is white. When it meets the water vapour produced from the hydrogen of the compound, it forms hydrated copper sulphate, CuSO4·5H2O, which is blue: CuSO4 + 5H2O → CuSO4·5H2O (blue). The blue colour confirms hydrogen. This is why the copper sulphate must be dry (anhydrous) before the test.
Detection is qualitative — it only answers 'is carbon or hydrogen present, yes or no' using the lime water and copper sulphate colour tests. Estimation (Liebig's method) is quantitative — it measures how much carbon and hydrogen by weighing the CO2 and H2O absorbed. NEET may test both, so keep the two ideas separate.
Yes. Carbon detection depends only on CO2 turning lime water milky, so a compound like carbon tetrachloride (CCl4) still shows carbon. In that case the copper sulphate stays white because there is no hydrogen to form water. The two tests are independent of each other.
Which one of the following reactions does NOT belong to Lassaigne's test?
Try the real previous-year questions from this chapter — each with the answer and a full solution.
Dry copper(II) oxide (CuO). On heating, it oxidises carbon to CO2 and hydrogen to water in a single setup, so one experiment can show both elements.
The gas produced turns lime water (calcium hydroxide) milky because insoluble white CaCO3 forms: CO2 + Ca(OH)2 → CaCO3 + H2O.
The water vapour produced turns white anhydrous copper sulphate blue by forming CuSO4·5H2O.
Only anhydrous (dry, white) CuSO4 can show a colour change. If it already contains water it is blue, so it could not react with the water from the compound to give a fresh blue colour.
It is detection — a qualitative test that only tells you whether carbon and hydrogen are present. Measuring the amount is done separately by Liebig's estimation method.