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NEET 2023 Phase 2 · ChemistryPrevious Year Question

Which amongst the following compounds will show geometrical isomerism?

Answer: (B) 3,4-Dimethylhex-3-ene. \textbf{Answer:} (b) 3,4-Dimethylhex-3-ene \textbf{Solution:} Geometrical (cis/trans) isomerism requires that each carbon of the C=C double bond bears two different groups.

  1. A.2-Methylprop-1-ene
  2. B.3,4-Dimethylhex-3-ene✓
  3. C.Pent-1-ene
  4. D.2,3-Dimethylbut-2-ene

Correct Answer

(B) 3,4-Dimethylhex-3-ene

Solution & Explanation

\textbf{Answer:} (b) 3,4-Dimethylhex-3-ene \textbf{Solution:} Geometrical (cis/trans) isomerism requires that each carbon of the C=C double bond bears two different groups. In 3,4-dimethylhex-3-ene, , each doubly bonded carbon carries an ethyl and a methyl group (different from each other), so cis and trans forms exist. 2-Methylprop-1-ene and 2,3-dimethylbut-2-ene each have a doubly bonded carbon bearing two identical groups, and pent-1-ene is a terminal alkene , so none of these show geometrical isomerism.

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