Chemistry · General Principles Of Organic Chemistry · NEET
Only ONE functional group can be the suffix, and it is the highest-priority (principal) group. For example, in a molecule that has both -OH and -Br, the -OH wins because it is a real functional group (suffix -ol), while -Br is only a substituent (prefix bromo-). So CH3-CH(Cl)-CH(CH3)-CH(OH)-CH2-CH2-Br is named as an -ol, giving 1-bromo-5-chloro-4-methylhexan-3-ol. The -OH decides the suffix and the numbering.
Number the longest chain from the end that gives the LOWEST number (locant) to the principal functional group (the one used as the suffix). The functional group's position beats substituents and double bonds. In 1-bromo-5-chloro-4-methylhexan-3-ol, numbering from the Br end puts -OH at C-3 (lower) instead of C-4, so that direction is correct.
The suffix is added at the END of the name and describes the principal functional group: -ol (alcohol), -al (aldehyde), -one (ketone), -oic acid (carboxylic acid), -amine (amine). A prefix is written at the FRONT for lower-priority groups and substituents: chloro-, bromo-, hydroxy-, oxo-, methyl-. One molecule has one suffix but can have many prefixes.
All prefixes (substituents) are written in ALPHABETICAL order, each with its own number. For example, 1-bromo-5-chloro-4-methyl... : bromo before chloro before methyl. Ignore multiplying words like di- and tri- when alphabetising (compare the base name, e.g. 'ethyl' vs 'methyl').
Pick the highest-priority group as the suffix (COOH > ester > amide > nitrile > aldehyde > ketone > alcohol > amine). Lower-priority groups become prefixes. In the 2017 NEET compound with -CHO, C=O and C=C, the aldehyde (-CHO) wins the suffix -al and gets C-1, the ketone becomes oxo/keto (prefix), giving 3-keto-2-methylhex-4-enal.
The double bond is shown by -ene inside the name with its own locant, placed just before the functional-group suffix. Example: hex-4-en-3-one, or in the aldehyde case hex-2-enal. The functional-group suffix still controls the main numbering, and the double bond just gets a number in between.
The IUPAC name of the compound (a six-carbon chain bearing a terminal -CHO, an adjacent CH3 branch, a ketone C=O, and a C=C double bond) is:
What is the IUPAC name of the product formed: CH3-CO-CH3 -> (i) C2H5MgBr, dry ether (ii) H2O/H+ ?
The correct IUPAC name of CH3-CH(Cl)-CH(CH3)-CH(OH)-CH2-CH2-Br is:
Try the real previous-year questions from this chapter — each with the answer and a full solution.
Prefixes (alphabetical substituents) + root word (chain length: meth/eth/prop...) + unsaturation (-ane/-ene/-yne) + suffix (functional group like -ol, -al, -one). Example: 1-bromo-5-chloro-4-methyl (prefixes) + hex (root) + an (saturated) + 3-ol (suffix).
A common NEET order (highest to lowest) is: carboxylic acid > ester > amide > nitrile > aldehyde > ketone > alcohol > amine. The highest one present becomes the suffix; the rest become prefixes.
Halogens (-Cl, -Br, -I, -F) are always treated as substituents (prefixes: chloro-, bromo-, iodo-, fluoro-), never as the suffix. So they never decide the numbering when a true functional group like -OH or -CHO is present.
When a ketone (C=O) is not the highest-priority group, it is written as a prefix 'oxo-' (or older 'keto-'). For example, in 3-keto-2-methylhex-4-enal the aldehyde is the suffix and the ketone becomes the keto/oxo prefix.
NEET regularly asks you to name a drawn structure or a reaction product, and to pick the correct locants. One naming question can decide a rank, so knowing suffix priority, lowest-locant rule, and alphabetical prefixes is essential.