IUPAC Naming of Compounds with Functional Groups

Chemistry · General Principles Of Organic Chemistry · NEET

To name a compound with a functional group, first find the longest carbon chain that contains the main functional group. Then name it using a suffix (like -ol for -OH, -al for -CHO, -one for C=O) and give that group the lowest possible number (locant). Memory hook: the "boss" functional group gets the suffix and the smallest number; everything else becomes a prefix listed in alphabetical order.
Naming a compound with a functional groupExample: CH3-CH(Cl)-CH(CH3)-CH(OH)-CH2-CH2-BrC6C5C4C3C2C1CH3ClCH3OHCH2Brsuffix -ol1-bromo-5-chloro-4-methylhexan-3-olOH gets lowest locant (C-3): number from Br end
The principal functional group (-OH) takes the suffix -ol and the lowest locant (C-3). Numbering runs from the Br end so -OH gets the smaller number; Cl, Br and CH3 are alphabetical prefixes.

Your doubts, answered

How do I choose which functional group becomes the suffix?

Only ONE functional group can be the suffix, and it is the highest-priority (principal) group. For example, in a molecule that has both -OH and -Br, the -OH wins because it is a real functional group (suffix -ol), while -Br is only a substituent (prefix bromo-). So CH3-CH(Cl)-CH(CH3)-CH(OH)-CH2-CH2-Br is named as an -ol, giving 1-bromo-5-chloro-4-methylhexan-3-ol. The -OH decides the suffix and the numbering.

How do I number the carbon chain correctly?

Number the longest chain from the end that gives the LOWEST number (locant) to the principal functional group (the one used as the suffix). The functional group's position beats substituents and double bonds. In 1-bromo-5-chloro-4-methylhexan-3-ol, numbering from the Br end puts -OH at C-3 (lower) instead of C-4, so that direction is correct.

What is the difference between a suffix and a prefix?

The suffix is added at the END of the name and describes the principal functional group: -ol (alcohol), -al (aldehyde), -one (ketone), -oic acid (carboxylic acid), -amine (amine). A prefix is written at the FRONT for lower-priority groups and substituents: chloro-, bromo-, hydroxy-, oxo-, methyl-. One molecule has one suffix but can have many prefixes.

In what order do I write the prefixes?

All prefixes (substituents) are written in ALPHABETICAL order, each with its own number. For example, 1-bromo-5-chloro-4-methyl... : bromo before chloro before methyl. Ignore multiplying words like di- and tri- when alphabetising (compare the base name, e.g. 'ethyl' vs 'methyl').

How do I name a compound that has more than one functional group?

Pick the highest-priority group as the suffix (COOH > ester > amide > nitrile > aldehyde > ketone > alcohol > amine). Lower-priority groups become prefixes. In the 2017 NEET compound with -CHO, C=O and C=C, the aldehyde (-CHO) wins the suffix -al and gets C-1, the ketone becomes oxo/keto (prefix), giving 3-keto-2-methylhex-4-enal.

Where does the double bond number go in the name?

The double bond is shown by -ene inside the name with its own locant, placed just before the functional-group suffix. Example: hex-4-en-3-one, or in the aldehyde case hex-2-enal. The functional-group suffix still controls the main numbering, and the double bond just gets a number in between.

⚠️ The NEET trap
Giving the lowest number to the carbon chain end nearest the double bond or a halogen, ignoring the -OH position.
The principal functional group (here -OH, suffix -ol) always gets the lowest locant first, even before double bonds and substituents.
🧠 NTA loves compounds with an -OH plus a Br and a C=C. Students number from the wrong end and get 4-ol instead of 3-ol. Rule: suffix group wins the smallest number, always.

Real NEET questions

NEET 2017

The IUPAC name of the compound (a six-carbon chain bearing a terminal -CHO, an adjacent CH3 branch, a ketone C=O, and a C=C double bond) is:

A · 3-keto-2-methylhex-4-enal
B · 5-formylhex-2-en-3-one
C · 5-methyl-4-oxohex-2-en-5-al
D · 3-keto-2-methylhex-5-enal
Solution: The aldehyde (-CHO) is the principal functional group, so it gets the suffix -al and the lowest locant C-1. Numbering from the CHO end: C-1 aldehyde, C-2 methyl branch, C-3 ketone (keto/oxo prefix), and the double bond between C-4 and C-5. This gives 3-keto-2-methylhex-4-enal. Priority order for numbering here is aldehyde > ketone > alkene.
NEET 2021

What is the IUPAC name of the product formed: CH3-CO-CH3 -> (i) C2H5MgBr, dry ether (ii) H2O/H+ ?

A · pentan-3-ol
B · 2-methylbutan-2-ol
C · 2-methylpropan-2-ol
D · pentan-2-ol
Solution: The Grignard reagent C2H5MgBr adds to the carbonyl carbon of acetone. After acidic workup the alkoxide is protonated to give a tertiary alcohol (CH3)2C(OH)C2H5. The -OH is the principal group (suffix -ol) at C-2, with a methyl branch at C-2, so the name is 2-methylbutan-2-ol.
NEET 2022

The correct IUPAC name of CH3-CH(Cl)-CH(CH3)-CH(OH)-CH2-CH2-Br is:

A · 1-bromo-5-chloro-4-methylhexan-3-ol
B · 6-bromo-2-chloro-4-methylhexan-4-ol
C · 1-bromo-4-chloro-5-chlorohexan-3-ol
D · 6-bromo-4-chloro-4-chlorohexan-4-ol
Solution: The chain has 6 carbons (hexane) and -OH is the principal group, so it gets the suffix -ol and the lowest locant. Numbering from the Br end gives -OH at C-3. Substituents (alphabetical): 1-bromo, 5-chloro, 4-methyl. Full name: 1-bromo-5-chloro-4-methylhexan-3-ol.

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Frequently asked

What is the correct order of parts in an IUPAC name?

Prefixes (alphabetical substituents) + root word (chain length: meth/eth/prop...) + unsaturation (-ane/-ene/-yne) + suffix (functional group like -ol, -al, -one). Example: 1-bromo-5-chloro-4-methyl (prefixes) + hex (root) + an (saturated) + 3-ol (suffix).

Which functional group has the highest priority for the suffix?

A common NEET order (highest to lowest) is: carboxylic acid > ester > amide > nitrile > aldehyde > ketone > alcohol > amine. The highest one present becomes the suffix; the rest become prefixes.

Is a halogen a functional group in IUPAC naming?

Halogens (-Cl, -Br, -I, -F) are always treated as substituents (prefixes: chloro-, bromo-, iodo-, fluoro-), never as the suffix. So they never decide the numbering when a true functional group like -OH or -CHO is present.

How is a ketone shown when it is not the principal group?

When a ketone (C=O) is not the highest-priority group, it is written as a prefix 'oxo-' (or older 'keto-'). For example, in 3-keto-2-methylhex-4-enal the aldehyde is the suffix and the ketone becomes the keto/oxo prefix.

Why does IUPAC naming matter for NEET?

NEET regularly asks you to name a drawn structure or a reaction product, and to pick the correct locants. One naming question can decide a rank, so knowing suffix priority, lowest-locant rule, and alphabetical prefixes is essential.