Chemistry · Some Basic Concepts Of Chemistry · NEET
You cannot jump straight from grams to particles. Always go grams -> moles -> particles. Step 1: moles = mass (g) / molar mass (g/mol). Step 2: particles = moles x 6.022 x 10^23. Example: 5.4 g of urea (molar mass 60). Moles = 5.4/60 = 0.09 mol. Molecules = 0.09 x 6.022 x 10^23 = 5.42 x 10^22 molecules. This exact chain appeared in NEET 2026.
Simple rule: moles -> particles means you MULTIPLY by 6.022 x 10^23 (one mole is a huge number of particles, so the count goes up). Particles -> moles means you DIVIDE by 6.022 x 10^23 (you are packing many particles into fewer moles). If your answer for number of atoms is smaller than the number of moles, you divided by mistake.
First find molecules using moles x NA. Then multiply by the number of atoms in one molecule (from the formula). Example: H2O has 3 atoms per molecule. 1 mole of water = 6.022 x 10^23 molecules = 3 x 6.022 x 10^23 atoms. For urea NH2CONH2 there are 4 H atoms per molecule, so H atoms = moles x 4 x NA. Forgetting this extra multiply is the most common NEET slip.
Divide by the molar mass of the whole substance you weighed. For O2 gas use 32 g/mol (not 16). For NaCl use 58.5 g/mol. Only after you have moles of the compound do you break it down into individual atoms using the formula. Weighing O2 and dividing by 16 is a classic trap.
Count every atom written in the chemical formula. Na2CO3 has 2 Na + 1 C + 3 O = 6 atoms per formula unit. CO2 has 3 atoms. NaOH has 3 atoms. He (monatomic) has 1. Total atoms = moles x (atoms per formula unit) x NA. This is exactly how NEET 2025 tested it.
Yes, but only at STP. For a gas at STP, moles = volume (L) / 22.4 L (older value) or / 22.7 L (new NCERT value). Then multiply by NA for particles. So a gas gives you a third road into moles: mass road (mass/molar mass), OR volume road (volume/molar volume). All roads meet at moles.
The number of hydrogen atoms present in 5.4 g of urea is (molar mass of urea = 60 g/mol; NA = 6.022 x 10^23 /mol)
Which one of the following has the maximum number of atoms? (A) 1 g of O2 [O=16] (B) 1 g of Li [Li=7] (C) 1 g of Ag [Ag=108] (D) 1 g of Mg [Mg=24]
Choose the ones with an equal number of atoms: A) 212 g Na2CO3 [106] B) 248 g Na2O [62] C) 240 g NaOH [40] D) 12 g H2 [2] E) 220 g CO2 [44]
Try the real previous-year questions from this chapter — each with the answer and a full solution.
Avogadro's number (NA) is 6.022 x 10^23. It is the number of particles (atoms, molecules or ions) in exactly one mole of any substance. NCERT writes it fully as about 602213670000000000000000.
Moles = mass / molar mass, and particles = moles x NA. Combine them: number of particles = (mass / molar mass) x NA. For atoms in a compound, multiply again by atoms per formula unit.
Mass and particle count are not directly linked - they connect only through the amount of substance, which is measured in moles. Moles is the bridge that molar mass and Avogadro's number both plug into, so every conversion must pass through it.
They are numerically equal but have different units and meaning. Molecular mass is in u (for one molecule); molar mass is the same number in g/mol (for one mole). Water is 18 u per molecule and 18 g/mol per mole.
At STP, moles = volume in litres / 22.4 L (or 22.7 L in the newest NCERT). Then multiply by NA for the number of molecules. This gives a volume route into moles for gases.