NEET 2026 (Phase 1) · ChemistryPrevious Year Question
The number of hydrogen atoms present in 5.4 g of urea is (molar mass of urea = 60 g mol$^{-1}$; $N_A = 6.022\times10^{23}$ mol$^{-1}$)
- A.$1.084\times10^{23}$
- B.$1.084\times10^{22}$
- C.$2.168\times10^{22}$
- D.$2.168\times10^{23}$✓
Correct Answer
(D) $2.168\times10^{23}$
Solution & Explanation
\textbf{Answer:} (D) $2.168\times10^{23}$ \textbf{Solution:} Urea \ce{NH2CONH2} has 4 H atoms per molecule. Moles of urea $= \dfrac{5.4}{60} = 0.09$ mol. H atoms $= 0.09\times 4\times 6.022\times10^{23} = 2.168\times10^{23}$.
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