NEET 2016 Phase 1 · ChemistryCarbohydratesPrevious Year Question
Which one given below is a non-reducing sugar?
Answer: (D) Sucrose. \textbf{Answer:} (D) Sucrose has no free anomeric carbon, so it is non-reducing.
- A.Maltose
- B.Lactose
- C.Glucose
- D.Sucrose✓
Correct Answer
(D) Sucrose
Solution & Explanation
\textbf{Answer:} (D) Sucrose has no free anomeric carbon, so it is non-reducing. \textbf{Solution:} In sucrose () the glycosidic linkage joins the anomeric carbon of glucose (C-1) to the anomeric carbon of fructose (C-2), so no free hemiacetal/hemiketal ( on anomeric C) group remains — hence it is non-reducing. Maltose and lactose each retain one free anomeric carbon, and glucose has a free ; all three are reducing sugars.
🎯
43,000+ questions in हिंदी & English · one-tap toggle
Open →📚Practice all NEET Chemistry PYQs chapter-wise →💡Don't get it? Learn the Biomolecules concepts →Practice NEET 2016 Phase 1 Chemistry — free, with instant solutions
43,000+ NEET questions solved step-by-step, chapter-wise, in the MedicNEET app.
More NEET PYQ solutions
ChemSucrose on hydrolysis gives:ChemThe correct order of decreasing acidity of the following aliphatic acids is:ChemWhich one of the following reactions does NOT belong to Lassaigne's test?ChemHow many products (including stereoisomers) are expected from the monochlorination of 2-methylbutane, (CH3)2CH-CH2-CH3?ChemThe total number of possible isomers (both structural as well as stereoisomers) of cyclic ethers of molecular formula C4H8O is:ChemAmong the given compounds I-III, the correct order of bond dissociation energy of the C-H bond marked with an asterisk (*) is:ChemThe correct order of decreasing basic strength of the given amines is:ChemMatch List I (Mixture) with List II (Method of Separation). List I A. CHCl3 + C6H5NH2 B. Crude oil in the petroleum industry C. Glycerol from spent-lye D. Aniline-water List II I. Distillation under reduced pressure II. Steam distillation III. Fractional distillation IV. Simple distillation
