The number of electrons delivered at the cathode during electrolysis by a current of $1$ ampere in $60$ seconds is (charge on electron $=1.60\times 10^{-19}$ C)

Solution & Explanation

\textbf{Answer:} (C) $3.75\times 10^{20}$ \textbf{Solution:} Charge passed: $Q=It=1\times 60=60\text{C}$. Each electron carries a charge of $1.60\times 10^{-19}$ C, so the number of electrons delivered is $$n=\frac{Q}{e}=\frac{60}{1.60\times 10^{-19}}=3.75\times 10^{20}.$$