NEET 2024 · ChemistryElectrolysisPrevious Year Question

Mass in grams of copper deposited by passing $9.6487$ A current through a voltmeter containing copper sulphate solution for $100$ seconds is: (Given: Molar mass of $Cu$ $= 63$ g mol $^{- 1}$ , $1 F = 96487$ C)

Answer: (A) 0.315 g. \textbf{Answer:} (A) 0.315 g \textbf{Solution:} At the cathode: $Cu X^{2 +} + 2 e X^{-} Cu$ ( $n = 2$ ).

A.0.315 g✓
B.31.5 g
C.0.0315 g
D.3.15 g

Correct Answer

(A) 0.315 g

Solution & Explanation

\textbf{Answer:} (A) 0.315 g \textbf{Solution:} At the cathode: $Cu X^{2 +} + 2 e X^{-} Cu$ ( $n = 2$ ). Charge passed: $Q = I t = 9.6487 \times 100 = 964.87 C$ . Using Faraday's first law $w = \frac{M \cdot Q}{n \cdot F}$ , $w = \frac{63 \times 964.87}{2 \times 96487} = \frac{964.87}{96487} \times \frac{63}{2} = 0.01 \times 31.5 = 0.315 g .$

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Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate solution for 100 seconds is: (Given: Molar mass of Cu =63 g mol−1, 1F=96487 C)

Solution & Explanation

More NEET PYQ solutions

Mass in grams of copper deposited by passing $9.6487$ A current through a voltmeter containing copper sulphate solution for $100$ seconds is: (Given: Molar mass of $Cu$ $= 63$ g mol $^{- 1}$ , $1 F = 96487$ C)