NEET 2016 Phase 2 · ChemistryPrevious Year Question

The correct increasing order of trans-effect of the following species is:

Answer: (B) $CN X^{-}$ > $C X_{6} H X_{5} X^{-}$ > $Br X^{-}$ > $NH X_{3}$ . \textbf{Answer:} (B) $CN X^{-}$ > $C X_{6} H X_{5} X^{-}$ > $Br X^{-}$ > $NH X_{3}$ .

A. $NH X_{3}$ > $CN X^{-}$ > $Br X^{-}$ > $C X_{6} H X_{5} X^{-}$
B. $CN X^{-}$ > $C X_{6} H X_{5} X^{-}$ > $Br X^{-}$ > $NH X_{3}$ ✓
C. $Br X^{-}$ > $CN X^{-}$ > $NH X_{3}$ > $C X_{6} H X_{5} X^{-}$
D. $CN X^{-}$ > $Br X^{-}$ > $C X_{6} H X_{5} X^{-}$ > $NH X_{3}$

Correct Answer

(B) $CN X^{-}$ > $C X_{6} H X_{5} X^{-}$ > $Br X^{-}$ > $NH X_{3}$

Solution & Explanation

\textbf{Answer:} (B) $CN X^{-}$ > $C X_{6} H X_{5} X^{-}$ > $Br X^{-}$ > $NH X_{3}$ . \textbf{Solution:} The trans-effect is the ability of a coordinated ligand to labilise (direct substitution at) the position trans to itself in square-planar complexes. Strong σ-donors and especially strong π-acceptor ligands show a high trans-effect. The standard trans-directing series places strong π-acceptors/σ-donors highest: $CN X^{-}$ ≈ $CO$ > $C X_{6} H X_{5} X^{-}$ > $Br X^{-}$ > $NH X_{3}$ (a weak σ-donor with no π-acceptance). Hence the correct ordering given in the options is $CN X^{-}$ > $C X_{6} H X_{5} X^{-}$ > $Br X^{-}$ > $NH X_{3}$ , option (B).

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