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NEET 2016 Phase 2 · ChemistryPrevious Year Question

Which of the following can be used as the halide component for a Friedel-Crafts reaction?

Answer: (D) Isopropyl chloride. \textbf{Answer:} (d) Isopropyl chloride \textbf{Solution:} Friedel-Crafts alkylation needs an alkyl halide that can ionise to a relatively stable carbocation.

  1. A.Chlorobenzene
  2. B.Bromobenzene
  3. C.Chloroethene
  4. D.Isopropyl chloride✓

Correct Answer

(D) Isopropyl chloride

Solution & Explanation

\textbf{Answer:} (d) Isopropyl chloride \textbf{Solution:} Friedel-Crafts alkylation needs an alkyl halide that can ionise to a relatively stable carbocation. Isopropyl chloride gives a secondary (2-propyl) carbocation, which is stable enough to act as the electrophile. Aryl and vinyl halides (chlorobenzene, bromobenzene, chloroethene) have bonds with partial double-bond character (halogen lone pair donated into the ring/ system), so they do not ionise to carbocations and cannot serve as the halide component. Hence (d).

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