NEET 2017 · ChemistryCarbonyl groupPrevious Year Question
The IUPAC name of the compound is:
Answer: (A) (A) 3-keto-2-methylhex-4-enal. \textbf{Answer:} (A) 3-keto-2-methylhex-4-enal \textbf{Solution:} The aldehyde group has the highest priority and takes the suffix \textit{-al}, so it is numbered C1.
- A.(A) 3-keto-2-methylhex-4-enal✓
- B.(B) 5-formylhex-2-en-3-one
- C.(C) 5-methyl-4-oxohex-2-en-5-al
- D.(D) 3-keto-2-methylhex-5-enal
Correct Answer
(A) (A) 3-keto-2-methylhex-4-enal
Solution & Explanation
\textbf{Answer:} (A) 3-keto-2-methylhex-4-enal \textbf{Solution:} The aldehyde group has the highest priority and takes the suffix \textit{-al}, so it is numbered C1. Along the six-carbon chain: C1 is , C2 bears the methyl substituent, C3 is the ketone carbon, and the double bond lies between C4 and C5. Combining the locants gives 3-keto-2-methylhex-4-enal.
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