NEET 2017 · ChemistryPrevious Year Question

Name the gas that can readily decolourise acidified $KMnO X_{4}$ solution:

Answer: (B) (b) $SO X_{2}$ . \textbf{Answer:} (b) $SO X_{2}$ \textbf{Solution:} $SO X_{2}$ acts as a reducing agent: it reduces $Mn (VII)$ in acidified $KMnO X_{4}$ (purple) to $Mn (II)$ (colourless), being itself oxidised to sulphate.

A.(a) $CO X_{2}$
B.(b) $SO X_{2}$ ✓
C.(c) $NO X_{2}$
D.(d) $P X_{2} O X_{5}$

Correct Answer

(B) (b) $SO X_{2}$

Solution & Explanation

\textbf{Answer:} (b) $SO X_{2}$ \textbf{Solution:} $SO X_{2}$ acts as a reducing agent: it reduces $Mn (VII)$ in acidified $KMnO X_{4}$ (purple) to $Mn (II)$ (colourless), being itself oxidised to sulphate. $2 KMnO X_{4} + 5 SO X_{2} + 2 H X_{2} O K X_{2} SO X_{4} + 2 MnSO X_{4} + 2 H X_{2} SO X_{4}$ Hence $SO X_{2}$ readily decolourises acidified $KMnO X_{4}$ . $CO X_{2}$ and $P X_{2} O X_{5}$ are not reducing, and $NO X_{2}$ does not decolourise it readily.

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Name the gas that can readily decolourise acidified KMnOX4​ solution:

Solution & Explanation

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Name the gas that can readily decolourise acidified $KMnO X_{4}$ solution: