NEET 2017 · PhysicsStored energyPrevious Year Question
A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting system
Answer: (B) Decreases by a factor of 2. Answer: (b) Solution: Charge Q is fixed; total capacitance doubles to 2C, so common V halves.
- A.Increases by a factor of 4
- B.Decreases by a factor of 2✓
- C.Remains the same
- D.Increases by a factor of 2
Correct Answer
(B) Decreases by a factor of 2
Solution & Explanation
Answer: (b) Solution: Charge Q is fixed; total capacitance doubles to 2C, so common V halves. U_i = ½CV²; U_f = ½(2C)(V/2)² = ¼CV² = U_i/2. Energy decreases by a factor of 2. → option (b).
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