NEET 2019 Odisha · PhysicsStored energyPrevious Year Question
Two identical capacitors C1 and C² of equal capacitance are connected as shown. Terminals a and b of key k are connected to charge capacitor C1 using a battery of emf V. Now disconnecting a and b, the terminals b and c are connected. Due to this, what will be the percentage loss of energy?
Answer: (C) 50%. Answer: (c) Solution: Charged C₁ shares charge with identical uncharged C₂ (equal capacitances).
- A.75%
- B.0%
- C.50%✓
- D.25%
Correct Answer
(C) 50%
Solution & Explanation
Answer: (c) Solution: Charged C₁ shares charge with identical uncharged C₂ (equal capacitances). Fraction lost = C₂/(C₁+C₂) = C/(2C) = 50%. → option (c).
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