NEET 2026 (Phase 1) · PhysicsStored energyPrevious Year Question
Consider two uncharged capacitors of equal capacitance 200 pF. One of them is charged by a 100 V supply and disconnected. Now this capacitor is connected to the uncharged capacitor. The amount of electrostatic energy lost in the process is:
Answer: (A) 0.5 × 10⁻⁶ J. Answer: (a) Solution: Loss = ½·(C₁C₂/(C₁+C₂))·V² = ½·(200×200/400 pF)·(100)² = ½·(100 × 10⁻¹²)·10⁴ = 0.5 × 10⁻⁶ J.
- A.0.5 × 10⁻⁶ J✓
- B.1.0 J
- C.1.0 × 10⁻⁶ J
- D.0.5 J
Correct Answer
(A) 0.5 × 10⁻⁶ J
Solution & Explanation
Answer: (a) Solution: Loss = ½·(C₁C₂/(C₁+C₂))·V² = ½·(200×200/400 pF)·(100)² = ½·(100 × 10⁻¹²)·10⁴ = 0.5 × 10⁻⁶ J. → option (a).
🎯
43,000+ questions in हिंदी & English · one-tap toggle
Open →📚Practice all NEET Physics PYQs chapter-wise →💡Don't get it? Learn the Electrostatic Potential And Capacitance concepts →Practice NEET 2026 (Phase 1) Physics — free, with instant solutions
43,000+ NEET questions solved step-by-step, chapter-wise, in the MedicNEET app.
More NEET PYQ solutions
PhysThe magnetic energy stored in an inductor of inductance 4 µH carrying a current of 2 A is:PhysA capacitor of capacitance C = 900 pF is charged fully by 100 V battery B. Then B is disconnected and connected to another uncharged capacitor of capacitance C = 900 pF. The electrostatic energy stored by the system (b) is:PhysA parallel plate capacitor has a uniform electric field 'E' in the space between the plates. If the distance between the plates is 'd' and the area of each plate is 'A' the energy stored in the capacitor is: (ε₀ = permittivity of free space)PhysTwo identical capacitors C1 and C² of equal capacitance are connected as shown. Terminals a and b of key k are connected to charge capacitor C1 using a battery of emf V. Now disconnecting a and b, the terminals b and c are connected. Due to this, what will be the percentage loss of energy?PhysThe electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, isPhysThe magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductancePhysA capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting systemPhysA capacitor of 2 μF is charged as shown in the diagram. When the switch S is turned to position 2, the percentage of its stored energy dissipated is: