NEET 2018 · ChemistryPrevious Year Question

The correct order of N-compounds in their decreasing order of oxidation states is

Answer: (C) (c) $HNO X_{3}$ , $NO$ , $N X_{2}$ , $NH X_{4} Cl$ . \textbf{Answer:} (c) $HNO X_{3}$ , $NO$ , $N X_{2}$ , $NH X_{4} Cl$ \textbf{Solution:} Assigning the oxidation number of N in each species: $HNO X_{3}$ $= + 5$ $NO$ $= + 2$ $N X_{2}$ $= 0$ $NH X_{4} Cl$ $= - 3$ The decreasing order of oxidation state is therefore $HNO X_{3}$ ( $+ 5$ ) > $NO$ ( $+ 2$ ) > $N X_{2}$ ( $0$ ) > $NH X_{4} Cl$ ( $- 3$ ), which is option (c).

A.(a) $HNO X_{3}$ , $NH X_{4} Cl$ , $NO$ , $N X_{2}$
B.(b) $HNO X_{3}$ , $NO$ , $NH X_{4} Cl$ , $N X_{2}$
C.(c) $HNO X_{3}$ , $NO$ , $N X_{2}$ , $NH X_{4} Cl$ ✓
D.(d) $NH X_{4} Cl$ , $N X_{2}$ , $NO$ , $HNO X_{3}$

Correct Answer

Solution & Explanation

\textbf{Answer:} (c) $HNO X_{3}$ , $NO$ , $N X_{2}$ , $NH X_{4} Cl$ \textbf{Solution:} Assigning the oxidation number of N in each species: $HNO X_{3}$ $= + 5$ $NO$ $= + 2$ $N X_{2}$ $= 0$ $NH X_{4} Cl$ $= - 3$ The decreasing order of oxidation state is therefore $HNO X_{3}$ ( $+ 5$ ) > $NO$ ( $+ 2$ ) > $N X_{2}$ ( $0$ ) > $NH X_{4} Cl$ ( $- 3$ ), which is option (c).

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