NEET 2019 Odisha · ChemistryDipole momentPrevious Year Question

Which of the following is the correct order of dipole moment?

Answer: (B) $BF X_{3}$ < $NF X_{3}$ < $NH X_{3}$ < $H X_{2} O$ . \textbf{Answer:} (B) $BF X_{3}$ < $NF X_{3}$ < $NH X_{3}$ < $H X_{2} O$ \textbf{Solution:} $BF X_{3}$ is trigonal planar and symmetric so $μ = 0$ ; in $NF X_{3}$ the bond dipoles oppose the lone-pair dipole (lower $μ$ ) whereas in $NH X_{3}$ they reinforce it (higher $μ$ ); $H X_{2} O$ (bent, $104. 5^{\circ}$ ) has the largest $μ$ ( $1.85 D$ ).

A. $NH X_{3}$ < $BF X_{3}$ < $NF X_{3}$ < $H X_{2} O$
B. $BF X_{3}$ < $NF X_{3}$ < $NH X_{3}$ < $H X_{2} O$ ✓
C. $BF X_{3}$ < $NH X_{3}$ < $NF X_{3}$ < $H X_{2} O$
D. $H X_{2} O$ < $NF X_{3}$ < $NH X_{3}$ < $BF X_{3}$

Correct Answer

(B) $BF X_{3}$ < $NF X_{3}$ < $NH X_{3}$ < $H X_{2} O$

Solution & Explanation

\textbf{Answer:} (B) $BF X_{3}$ < $NF X_{3}$ < $NH X_{3}$ < $H X_{2} O$ \textbf{Solution:} $BF X_{3}$ is trigonal planar and symmetric so $μ = 0$ ; in $NF X_{3}$ the bond dipoles oppose the lone-pair dipole (lower $μ$ ) whereas in $NH X_{3}$ they reinforce it (higher $μ$ ); $H X_{2} O$ (bent, $104. 5^{\circ}$ ) has the largest $μ$ ( $1.85 D$ ). Hence $BF X_{3}$ < $NF X_{3}$ < $NH X_{3}$ < $H X_{2} O$ .

🎯

43,000+ questions in हिंदी & English · one-tap toggle

Practice NEET 2019 Odisha Chemistry — free, with instant solutions

43,000+ NEET questions solved step-by-step, chapter-wise, in the MedicNEET app.

Open →📚Practice all NEET Chemistry PYQs chapter-wise →💡Don't get it? Learn the Chemical Bonding concepts →

← Chemistry Q1 Chemistry Q3 →

More NEET PYQ solutions

ChemThe correct order of dipole moments for molecules NH3, H2S, CH4 and HF, is ChemWhich of the following set of molecules will have zero dipole moment?ChemThe correct order of decreasing acidity of the following aliphatic acids is:ChemWhich one of the following reactions does NOT belong to Lassaigne's test?ChemHow many products (including stereoisomers) are expected from the monochlorination of 2-methylbutane, (CH3)2CH-CH2-CH3?ChemThe total number of possible isomers (both structural as well as stereoisomers) of cyclic ethers of molecular formula C4H8O is:ChemAmong the given compounds I-III, the correct order of bond dissociation energy of the C-H bond marked with an asterisk (*) is:ChemThe correct order of decreasing basic strength of the given amines is:

More: All NEET 2019 Odisha Chemistry PYQs · NEET Chemistry PYQs · All NEET PYQs · Previous year papers