The correct order of dipole moments for molecules NH3, H2S, CH4 and HF, is

Correct answer: (B) HF > NH3 > H2S > CH4. Answer: (B) HF > NH3 > H2S > CH4 Solution: Dipole moments: HF ( 1.91,D) > NH3 ( 1.47,D) > H2S ( 0.97,D) > CH4 ( = 0, tetrahedral, symmetric, nonpolar). Higher electronegativity difference and molecular geometry govern net dipole.

NEET 2023 Phase 2 · ChemistryDipole momentPrevious Year Question

The correct order of dipole moments for molecules $NH X_{3}$ , $H X_{2} S$ , $CH X_{4}$ and $HF$ , is

Answer: (B) $HF$ > $NH X_{3}$ > $H X_{2} S$ > $CH X_{4}$ . \textbf{Answer:} (B) $HF$ > $NH X_{3}$ > $H X_{2} S$ > $CH X_{4}$ \textbf{Solution:} Dipole moments: $HF$ ( $\sim 1.91 D$ ) > $NH X_{3}$ ( $\sim 1.47 D$ ) > $H X_{2} S$ ( $\sim 0.97 D$ ) > $CH X_{4}$ ( $μ = 0$ , tetrahedral, symmetric, nonpolar).

A. $NH X_{3}$ > $HF$ > $CH X_{4}$ > $H X_{2} S$
B. $HF$ > $NH X_{3}$ > $H X_{2} S$ > $CH X_{4}$ ✓
C. $CH X_{4}$ > $H X_{2} S$ > $NH X_{3}$ > $HF$
D. $H X_{2} S$ > $NH X_{3}$ > $HF$ > $CH X_{4}$

Correct Answer

(B) $HF$ > $NH X_{3}$ > $H X_{2} S$ > $CH X_{4}$

Solution & Explanation

\textbf{Answer:} (B) $HF$ > $NH X_{3}$ > $H X_{2} S$ > $CH X_{4}$ \textbf{Solution:} Dipole moments: $HF$ ( $\sim 1.91 D$ ) > $NH X_{3}$ ( $\sim 1.47 D$ ) > $H X_{2} S$ ( $\sim 0.97 D$ ) > $CH X_{4}$ ( $μ = 0$ , tetrahedral, symmetric, nonpolar). Higher electronegativity difference and molecular geometry govern net dipole.

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The correct order of dipole moments for molecules NHX3​, HX2​S, CHX4​ and HF, is

Solution & Explanation

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The correct order of dipole moments for molecules $NH X_{3}$ , $H X_{2} S$ , $CH X_{4}$ and $HF$ , is