NEET 2019 Odisha · ChemistryPrevious Year Question
In a hydrogen atom, the de Broglie wavelength of an electron in the second Bohr orbit is: [Given that Bohr radius pm]
Answer: (B) pm. \textbf{Answer:} (B) pm \textbf{Solution:} Bohr quantization gives .
- A.211.6 pm
- B. pm✓
- C. pm
- D.105.8 pm
Correct Answer
(B) pm
Solution & Explanation
\textbf{Answer:} (B) pm \textbf{Solution:} Bohr quantization gives . Here pm. So pm.
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