The number of sigma ( ) and pi ( ) bonds in pent-2-en-4-yne is

Correct answer: (A) 10 bonds and 3 bonds. Answer: (a) 10 bonds and 3 bonds Solution: Pent-2-en-4-yne is CH3-CH=CH-C#CH. Sigma bonds: 4 C-C bonds along the 5-carbon skeleton + 6 C-H bonds (3 on C1, 1 on C2, 1 on C3, 1 on C5) = 10 bonds. Pi bonds: 1 from the C=C double bond + 2 from the C C triple bond = 3 bonds. Hence the molecule has 10 and 3 bonds.

NEET 2019 · ChemistryPrevious Year Question

The number of sigma ( $σ$ ) and pi ( $π$ ) bonds in pent-2-en-4-yne is

Answer: (A) 10 $σ$ bonds and 3 $π$ bonds. \textbf{Answer:} (a) 10 $σ$ bonds and 3 $π$ bonds \textbf{Solution:} Pent-2-en-4-yne is $CH X_{3} - CH = CH - C \equiv CH$ .

A.10 $σ$ bonds and 3 $π$ bonds✓
B.8 $σ$ bonds and 5 $π$ bonds
C.11 $σ$ bonds and 2 $π$ bonds
D.13 $σ$ bonds and no $π$ bonds

Correct Answer

(A) 10 $σ$ bonds and 3 $π$ bonds

Solution & Explanation

\textbf{Answer:} (a) 10 $σ$ bonds and 3 $π$ bonds \textbf{Solution:} Pent-2-en-4-yne is $CH X_{3} - CH = CH - C \equiv CH$ . Sigma bonds: 4 C-C $σ$ bonds along the 5-carbon skeleton + 6 C-H $σ$ bonds (3 on C1, 1 on C2, 1 on C3, 1 on C5) = 10 $σ$ bonds. Pi bonds: 1 $π$ from the C=C double bond + 2 $π$ from the C $\equiv$ C triple bond = 3 $π$ bonds. Hence the molecule has 10 $σ$ and 3 $π$ bonds.

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The number of sigma (σ) and pi (π) bonds in pent-2-en-4-yne is

Solution & Explanation

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The number of sigma ( $σ$ ) and pi ( $π$ ) bonds in pent-2-en-4-yne is